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2 years ago

What is a dominant trait and a recessive trait

Chemistry

2 answers:

guajiro [1.7K]2 years ago

5 0

Answer:

Dominant traits are always expressed when the connected allele is dominant, even if only one copy exists. Recessive traits are expressed only if both the connected alleles are recessive.

Explanation:

Freckles, cleft chin and dimples are all examples of a dominant trait.

nalin [4]2 years ago

3 0

Examples are freckles

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Which drug treats heartburn by neutralizing the acidity of the stomach by combining with hydrochloric acid (hcl) and increasing

natta225 [31]

Is italuminum hydroxide

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3 years ago

A (what) forms when the sperm first fertilizes an egg

Arlecino [84]

Fertilization occurs when the nucleus of both a sperm and egg fuse to form a diploid cell known as zygote the successful fusion of gametes forms a new organization

7 0

3 years ago

Give the following for SO2 and BrF5:

frosja888 [35]

Answer:

The given molecules are SO2 and BrF5.

Explanation:

Consider the molecule SO2:

The central atom is S.

The number of domains on S in this molecule is three.

Domain geometry is trigonal planar.

But there is a lone pair on the central atom.

So, according to VSEPR theory,

the molecular geometry becomes bent or V-shape.

Hybridization on the central atom is

$sp^{2}$ .

Consider the molecule BrF5:

The central atom is Br.

The number of domains on the central atom is six.

Domain geometry is octahedral.

But the central atom has a lone pair of electrons.

So, the molecular geometry becomes square pyramidal.

The hybridization of the central atom is $sp^{3} d^{2}$ .

The shapes of SO2 and BrF5 are shown below:

6 0

2 years ago

For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2 NO ( g

enyata [817]

Answer:

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

Explanation:

2 NO (g) + O₂ (g) ⇄ 2NO₂ (g)

Let's apply the thermodynamic formula to calculate the ΔG

ΔG = ΔG° + R .T . lnQ

We don't know if the gases are at equilibrium, that's why we apply Q (reaction quotient)

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln Q

How can we know Q? By the partial pressures (Qp)

P NO = 0.450atm

PO₂ = 0.1 atm

PNO₂ = 0.650 atm

Qp = [NO₂]² / [NO]² . [O₂]

Qp = 0.650² / 0.450² . 0.1 = 20.86

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln 20.86

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

5 0

3 years ago

The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.

azamat

Answer:

(a) $m_{gold}=7.322g$

(b)

$V_{gold}=0.379cm^3$

$V_{copper}=0.122cm^3$

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign as shown below:

$m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g$

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

$V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3$

$m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3} \\\\V_{copper}=0.122cm^3$

$\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\ \\\rho _{coin}=15.94g/cm^3$

Best regards.

3 0

3 years ago

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