Answer:
A.) 4.0
Explanation:
The general equilibrium expression looks like this:
![K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%20%7D)
In this expression,
-----> K = equilibrium constant
-----> uppercase letters = molarity
-----> lowercase letters = balanced equation coefficients
In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.
<----- Equilibrium expression
![K = \frac{[2 M] [2 M]}{[1 M] [1 M] }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5B2%20M%5D%20%5B2%20M%5D%7D%7B%5B1%20M%5D%20%5B1%20M%5D%20%7D)
<----- Insert molarities
<----- Multiply
<----- Divide
The mass of Hydrogen is 2 g/mol
The mass of Helium is 4 g/mol
G(2)=2
For this, you can plug in 2 everywhere you see an n. So the equation will read:
g(2)=g(2-1)+2 -> g(2)=g(1)+2. Since we are given g(1)=0, we can plug in 0 where we see g(1). The equation is now. g(2)=0+2. So, g(2)=2.
1. Complete ionization in water.
2. Ionization constant.
3. A good hydrogen-ion acceptor.
4. Weak acid.
5. This base ionizes slightly in aqueous.
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