Answer:
8.73 L
Explanation:
First, you need to convert grams to moles using the molar mass.
Molar Mass (N₂): 2(14.009 g/mol)
Molar Mass (N₂): 28.018 g/mol
12.2 grams N₂ 1 mole
---------------------- x ------------------------ = 0.435 moles N₂
28.018 grams
To find the volume, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (torr)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (62.36 torr*L/mol*K)
-----> T = temperature (K)
After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation.
P = 1132 torr R = 62.36 torr*L/mol*K
V = ? L T = 91 °C + 273.15 = 364.15 K
n = 0.435 moles
PV = nRT
(1132 torr)V = (0.435 moles)(62.36 torr*L/mol*K)(364.15 K)
(1132 torr)V = 9888.015
V = 8.73 L
Answer:
2 moles of Methane gas will occupy 44.8 L
Explanation:
If one mole of any gas occupies 22.4 L under certain conditions of temperature and pressure, and those conditions are assumed in this question, then we comfortably solve this problem as follows;
1 mole of Methane gas ---------------> 22.4 L
2 moles of Methane gas -------------->?
Cross and multiply, 2 moles of Methane gas = 2 X 22.4 L = 44.8L
Therefore, 2 moles of Methane gas will occupy 44.8 L, if the conditions of temperature and pressure are maintained.
OPTION A IS THE RIGHT SOLUTION.
If you can't answer a question, then make an educated guess.
