Answer:
2 boxes
Step-by-step explanation:
do 16 times 2 you get 32 so there are 32 green crayons 32/9 9 times 3 is 36 which is over 32 so you cant fill 3 boxes 9 times 2 equals 27 so the answer would be she can fill 2 boxes
the complete question in the attached figureLet
A°-----------> <span>the same central angle
</span><span>
For the larger circlelength of larger circle=2*pi*r-------> 2*pi*12-----> 75.36 m
360</span>°<span> (full circle) has a length of------------> 75.36 m
A</span>°-----------------------------------> 16 m
A°=(16)*360/75.36--------> A=76.43°
For the smaller circlelength of smaller circle=2pi*r-------> 2*pi*7.5-----> 47.1 m
360° (full circle) has a length of------------> 47.1 m
76.43°-----------------------------------> X
X=76.43*47.1/360-----> X=10 m ----> length arc of the smaller circle
the answer isthe length arc of the smaller circle is 10 m
Attached the solution and work.
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.