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arsen [322]
3 years ago
11

How does Earth's surface and the structures on the surface change as a result of an earthquake?

Physics
1 answer:
olga2289 [7]3 years ago
8 0

THE CHANGE IN EARTH SURFACE IS DUE TO VIBRATION AND COLLISION IN EARTH TECTONIC PLATES

Explanation:

  • VIBRATION is the change in the stable state/equilibrium state caused by increased pressure in a particular object or a surface due to electro magnetic wave
  • COLLISION is the meeting point of two or more surfaces or the objects
  • During earthquake the tectonic plates of the earth surface begins to collide or cause any irregular drastic movements
  • This is due to the vibration caused by earthquake
  • This causes the shake in the upper surface which results in construction damage and calamities
  • This causes drastic change in the surface of the earth.
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Con lắc lò xo có độ cứng k = 100N/m được gắn vật có khối lượng m=0.1kg, kéo vật ra khỏi vị trí cân bằng 1 đoạn 5cm rồi buông tay
Delvig [45]

Answer:

The maximum velocity is 1.58 m/s.

Explanation:

A spring pendulum with stiffness k = 100N/m is attached to an object of mass m = 0.1kg, pulls the object out of the equilibrium position by a distance of 5cm, and then lets go of the hand for the oscillating object. Calculate the achievable vmax.

Spring constant, K = 100 N/m

mass, m = 0.1 kg

Amplitude, A = 5 cm = 0.05 m

Let the angular frequency is w.

w = \sqrt{K}{m}\\\\w = \sqrt{100}{0.1}\\\\w = 31.6 rad/s

The maximum velocity is

v_{max} = w A\\\\v_{max} = 31.6\times 0.05 = 1.58 m/s

8 0
3 years ago
An airplane travels at 300 mi/h south for 2.00 h and then at 250 mi/h north for 750 miles. What is the average speed for the tri
Anettt [7]

Answer:

270 mi/h

Explanation:

Given that,

To the south,

v₁ = 300 mi/h, t₁ = 2 h

We can find distance, d₁

d_1=v_1\times t_1\\\\d_1=300\times 2\\\\d_1=600\ \text{miles}

To the north,

v₂ = 250 mi/h, d₂ = 750 miles

We can find time, t₂

t_2=\dfrac{d_2}{v_2}\\\\t_2=\dfrac{750\ \text{miles}}{250\ \text{mi/h}}\\\\t_2=3\ h

Now,

Average speed = total distance/total time

V=\dfrac{d_1+d_2}{t_1+t_2}\\\\V=\dfrac{600+750}{2+3}\\\\V=270\ \text{mi/h}

Hence, the average speed for the trip is 270 mi/h.

3 0
3 years ago
While on an ice-fishing trip, you find yourself holding a 10 kg fish but stuck in the middle of
Anna007 [38]

The forward force you exert on the fish and your backward action will allow you to reach the shore.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

Fa = -Fb

Let's assume the fish is held in the hook, this will give you the opportunity to throw the fish forward while still holding it.

When the the fish is thrown forward, you will move backwards with an equal force based on Newton's third law. Your backward momentum towards the shore will help to maintain equal linear momentum between you and the fish.

Thus, this forward force of the fish and your backward action will allow you to reach the shore.

Learn more Newton's third law of motion here: brainly.com/question/25998091

3 0
2 years ago
Calculate the force exerted on the wall assuming that force is horizontal and using the data in the schematic representation of
Jlenok [28]

Answer:

1.93 x 10∧3 N

Explanation:

The picture attached shows the calculation

8 0
3 years ago
A bullet of mass m=26g is fired into a wooden block of mass M=4.7kg. The block is attached to a string of length 1.5m. The bulle
vodka [1.7K]

Answer:

u = 449 m/s

Explanation:

Given,

Mass of the bullet, m = 26 g

Mass of the wooden block,M = 4.7 Kg

height of the block,h = 0.31 m

initial speed of the block, u = ?

Using conservation of energy

(M+ m)gh = \dfrac{1}{2}(M+m)v^2

gh = \dfrac{1}{2}v^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.81\times 0.31}

v = 2.47 m/s

Now, using conservation of momentum to calculate the speed of the bullet.

m u + M u' = (M+m)v

m u  = (M+m)v

0.026 x u  = (4.7+0.026) x 2.47

u = 449 m/s

Hence, the speed of the bullet is equal to 449 m/s.

5 0
3 years ago
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