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2 years ago

How does Earth's surface and the structures on the surface change as a result of an earthquake?

Physics

1 answer:

olga2289 [7]2 years ago

8 0

THE CHANGE IN EARTH SURFACE IS DUE TO VIBRATION AND COLLISION IN EARTH TECTONIC PLATES

Explanation:

VIBRATION is the change in the stable state/equilibrium state caused by increased pressure in a particular object or a surface due to electro magnetic wave
COLLISION is the meeting point of two or more surfaces or the objects
During earthquake the tectonic plates of the earth surface begins to collide or cause any irregular drastic movements
This is due to the vibration caused by earthquake
This causes the shake in the upper surface which results in construction damage and calamities
This causes drastic change in the surface of the earth.

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Modern nuclear bomb tests have created an extra high level of14C in our atmosphere. When future archaeologistsdate samples from

Ipatiy [6.2K]

Answer:

Too old(Ex. if real time is 1000 then they estimate >1000)

Explanation:

This is because with time our planet may have a definite function which describes temperature.(Because of all the factors and global warming except nuclear bomb testing)

Now nuclear test on planet have significant effect on temperature rise.

Also 14°C rise in temperature is good one because of this.

If future archaeologists only consider that uniform function as above mentioned then they estimate more time then the real one.

Thus too old is right answer.

8 0

3 years ago

A gas heated to millions of degrees would emit

makkiz [27]

A gas heated to millions of degrees would emit mostly x-rays.

4 0

3 years ago

Two separate masses on two separate springs undergo simple harmonic motion indefinitely (the surface is frictionless). In CASE 1

Artemon [7]

Answer:

$\frac{F_1}{F_2} =\frac{1}{2}$

Explanation:

Assuming the we have to find ratio maximum forces on the mass in each case

we know that in a spring mass system

F= Kx

K= spring constant

x= spring displacement

Case 1:

$F_1=2k\times d$

case 2:

$F_2=2k\times 2d$

therefore, $\frac{F_1}{F_2} = \frac{2K\times d}{2K\times 2d}$

$\frac{F_1}{F_2} =\frac{1}{2}$

4 0

3 years ago

Add these measurements, using significant digit rules:

tia_tia [17]

Here we have to add the two measurements given in the question

The measurement values are given as 1.0090 cm and 0.02 cm.we have to add them on the basis of significant figure rules.

As per the addition rule in terms of significant figures

1-First we have to select the number of significant digits after the decimal point of each quantity.

2-Now we have to remember that during the addition ,the resultant of two quantities will follow the quantity having least number of significant figures after the decimal point.

3-Here we are considering the minimum number of significant figures after the decimal points not the minimum number of significant figures in case of multiplication and division

Now we have to add these two quantities as per the above rule-

1.0090 cm +0.02 cm

=1.0290 cm

Here the result will follow 0.02 which has minimum number of significant figures after the decimal points.

Hence we have to round off the number from 9 of 1.0290

As 9 is greater than 5 ,so he actual result will be 1.03 cm

3 0

2 years ago

A stationary siren on a firehouse is blaring at 81Hz. Assume the speed of sound to be 343m/s. What is the frequency perceived by

inn [45]

For a stationary siren on a firehouse is blaring at 81Hz. Assume the speed of sound to be 343m/s, the frequency perceived is mathematically given as'

F=81.721Hz

<h3>What is the frequency perceived by a firefighter racing toward the station at 11km/h?</h3>

Generally, the equation for the doppler effect is mathematically given as

$F'=\frac{vs+v}{vs}*f$

Therefore

F=81(343+3.05556)/343

F=81.721Hz

In conclusion, the frequency is

F=81.721Hz