Answer:
The maximum velocity is 1.58 m/s. 
Explanation:
A spring pendulum with stiffness k = 100N/m is attached to an object of mass m = 0.1kg, pulls the object out of the equilibrium position by a distance of 5cm, and then lets go of the hand for the oscillating object. Calculate the achievable vmax. 
Spring constant, K = 100 N/m 
mass, m = 0.1 kg 
Amplitude, A = 5 cm = 0.05 m 
Let the angular frequency is w. 

The maximum velocity is 

 
        
             
        
        
        
Answer:
270 mi/h
Explanation:
Given that,
To the south, 
v₁ = 300 mi/h, t₁ = 2 h
We can find distance, d₁

To the north, 
v₂ = 250 mi/h, d₂ = 750 miles
We can find time, t₂

Now,
Average speed = total distance/total time

Hence, the average speed for the trip is 270 mi/h.
 
        
             
        
        
        
The forward force you exert on the fish and your backward action will allow you to reach the shore.
<h3>
Newton's third law of motion</h3>
Newton's third law of motion states that for every action, there is an equal and opposite reaction.
Fa = -Fb
Let's assume the fish is held in the hook, this will give you the opportunity to throw the fish forward while still holding it. 
When the the fish is thrown forward, you will move backwards with an equal force based on Newton's third law. Your backward momentum towards the shore will help to maintain equal linear momentum between you and the fish.
Thus, this forward force of the fish and your backward action will allow you to reach the shore.
Learn more Newton's third law of motion here: brainly.com/question/25998091
 
        
             
        
        
        
Answer:
1.93 x 10∧3 N
Explanation:
The picture attached shows the calculation
 
        
             
        
        
        
Answer:
u = 449 m/s
Explanation:
Given,
Mass of the bullet, m = 26 g
Mass of the wooden block,M = 4.7 Kg
height of the block,h = 0.31 m
initial speed of the block, u = ?
Using conservation of energy




v = 2.47 m/s
Now, using conservation of momentum to calculate the speed of the bullet.
m u + M u' = (M+m)v
m u  = (M+m)v
0.026 x u  = (4.7+0.026) x 2.47
u = 449 m/s
Hence, the speed of the bullet is equal to 449 m/s.