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Pani-rosa [81]
2 years ago
6

19 8 How do you rename this as a mixed number

Mathematics
2 answers:
leonid [27]2 years ago
8 0

Answer:

Assuming you meant 19/8, the answer would be 2 and 3/8

Step-by-step explanation:

How many times does 8 go into 19? Twice, plus you will have 3 leftover since 8 x 2 is only 16 and not 19. That 2 stays a 2 and the left over 3 is 3/8, so your answer is 2 + 3/8

insens350 [35]2 years ago
5 0

Answer:

2 3/8

Step-by-step explanation:

You might be interested in
Use a benchmark fraction to compare 7 10 ths and 5 12 ths. Explain how you found the answer
elixir [45]
<span>Benchmark fractions are created when we make two different fractions have the same numerator or denominator. In thisi case, we will produce the same denominator. The LCM of 10 and 12 is 60. So the fractions become 42/60 and 25/60. Since the fraction with the larger numerator has a larger value when the denominators are the same, 7/10 is larger than 5/12.</span>
5 0
3 years ago
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen
devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = \frac{\sum X}{n} = 441

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 14.34

            n = sample size = 16

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<em />

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X -2.131 \times {\frac{s}{\sqrt{n} } } , \bar X +2.131 \times {\frac{s}{\sqrt{n} } } ]

                                      = [ 441-2.131 \times {\frac{14.34}{\sqrt{16} } } , 441+2.131 \times {\frac{14.34}{\sqrt{16} } } ]

                                      = [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0
3 years ago
How many solutions does 5x-y=2 5x-y=-2 have?
alekssr [168]

Answer:

No Solution.

Step-by-step explanation:

5x-y=2

5x-y=-2

-------------

-(5x-y)=-2

5x-y=-2

----------------

-5x+y=-2

5x-y=-2

-------------

0=-4

no solution

7 0
3 years ago
You must fast before having bloodwork done for your insurance company. The last time you had something to eat was at 9:30 pm. At
luda_lava [24]
10 hours 45 minutes :)
3 0
2 years ago
PLEASE HELP IT’S DUE TMR
Soloha48 [4]
4 + 3 + 1 = 8

450000 divided by 8 = 56250

The first person gets 225000.

The second person gets 168750.

The last person gets 56250.

pls give me brainliest if it helped:)
4 0
2 years ago
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