1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lawyer [7]
3 years ago
13

What is the reaction energy q of this reaction? use c2=931.5mev/u. express your answer in millions of electron volts to three si

gnificant figures?
Chemistry
1 answer:
Ann [662]3 years ago
5 0
₉₂U²³⁵ + ₀n¹ → ₅₄Xe¹⁴⁰ + ₃₈Sr⁹⁴ + 2 ₀n¹
Mass of reactants = 235.04393 + 1.008665 = 236.052595 amu
Mass of products = 139.92144 + 93.91523 + 2* (1.008665) = 235.854000 amu
Mass defect Δ m = 236.052595 - 235.854000 = 0.198 amu
Reaction energy released Q = Δ m * 931.5
                                              = 0.198 * 931.5 = 185 MeV
You might be interested in
How many grams nano3 add to 500g of h20 prepare solution .5 molal nano3?
Scilla [17]
Answer is: mass of sodium nitrate is 21,25 g.
m(H₂O) = 500 g · 1 kg/1000 g = 0,5 kg.
b(solution) = 0,500 m = 0,500 mol/kg.
m(NaNO₃) = ?
b(solution) = n(NaNO₃) ÷ m(H₂O).
n(NaNO₃) = 0,500 mol/kg · 0,5 kg.
n(NaNO₃) = 0,25 mol.
m(NaNO₃) = n(NaNO₃) · M(NaNO₃).
m(NaNO₃) = 0,25 mol · 85 g/mol.
m(NaNO₃) = 21,25 g.
8 0
3 years ago
Which of the following statements is true about Planck’s Law?
zimovet [89]
What are the answer choices?
5 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
3 years ago
Which compound contains a double bond?
just olya [345]
The answer would be ethane (C2H4)
7 0
3 years ago
When one atom contributes both bonding electrons in a single covalent bond, the bond is called a(n) ____?
andre [41]
Coordinate covalent bond 
7 0
4 years ago
Read 2 more answers
Other questions:
  • Why should carbonated beverages be kept cold?
    8·1 answer
  • What do you think would happen to the organisms in a food chain if the Sun stopped shining? Explain your answer in 3-5 sentences
    11·1 answer
  • Uranium-236 is ____.
    13·2 answers
  • a boy pulls a wagon with a force of 6 N east as another boy pushes it with a force of 4 N east. what is the net force?
    9·2 answers
  • Why is ice melting a physical change?
    7·1 answer
  • Which of the samples pictured is most likely a nonmetal?
    5·1 answer
  • Is supports combustion a chemical or physical property
    9·2 answers
  • Sama veda Tagalog <br><br><br>hokdog penge answer​
    6·1 answer
  • Hi anyone there who can talk to. me ans this and talk to me in comments​​
    13·1 answer
  • How is the element lead formed?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!