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Aleks [24]
3 years ago
8

A cube has sides of length 2 meters. Explain what happens to the volume of the cube if the length of the sides is doubled.

Mathematics
2 answers:
ohaa [14]3 years ago
5 0
Volume of a cube with side lengths of 2, 2, and 2. 
2³=8 m³


Volume of a cube with 4,4, and 4
4³=64 m³

Conclusion: The volume would be squared, or square rooted, depending on which way you are going.
Fudgin [204]3 years ago
5 0
If the length of the sides are doubled, the volume of the cube is 8 times the original.


Explanation:
The formula for volume of a rectangular prism is v = lxwxh (l is length, w is width and h is height.) So first we find the volume of the cube, 2x2x2 = 8. Now, we double the sides, so they become 4 meters. Then we find volume of the new cube, 4x4x4 = 64. To find the relationship between the volume of the new cube and the volume of the original cube, we divide 64 by 8, which gives us 8. Therefore, the volume of the new cube is 8 times the volume of the original cube
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Given a right triangle with legs a, b and hypotenuse c, solve for b if a= 72 and c= 75
kotykmax [81]

Answer:

The answer is a. 21.

Step-by-step explanation:

We solve this question by using Pythagoras theorem to relate the sides of a right angled triangle.

Here,

Hypotenuse of the given triangle(c)=75

Two sides of right angled triangle are:

a=72

b=?

Then,

for a given right angled triangle abc,

Using Pythagoras theorem,

c=\sqrt{a^{2} +b^{2} }

Squaring on both sides,

c^{2} =a^{2}+b^{2}

or,75^{2}=72^{2}+b^{2}

or, b^{2}=75^{2}-72^{2}

or,b^{2}=5625- 5184

or,b^{2} =441

∴b=21

So, the value of b is obtained to 21 by the use of Pythagoras theorem.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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