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musickatia [10]
3 years ago
15

What was the cause of Dede's condition?

Biology
1 answer:
Dmitriy789 [7]3 years ago
7 0
Who is Dede and what are her symptoms. We need more context
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When Mendel crossed yellow- seeded and green- seeded pea plants, all the offspring were yellow seeded. When he took these F1 yel
lisabon 2012 [21]

Answer:

genotypic ratio = 2:2

Explanation:

We were being told that when Mendel crossed yellow- seeded and green- seeded pea plants, all the offspring were yellow seeded.

This implies that the Yellow seed trait masked the green seed trait in the F1 generation. The best defination that can be deduced is that;

the yellow-seeded plants are homozygous dominant &

the green-seed pea plants are homozygous recessive

So, let yellow- seeded pea plants= YY

and green- seeded pea plants= gg

i.e YY × gg

  | Y | Y

g | Yg | Yg  

g | Yg | Yg

F₁ = (Yg, Yg, Yg, Yg,) All the offspring were heterozygous yellow seeded plant.

Now, when he crossed the F₁ heterozygous yellow seeded plant with the green- seeded plants; we will have the following result

i.e Yg × gg

  | Y | g

g | Yg | gg  

g | Yg | gg

F₂ = (Yg, Yg, gg, gg)

The F₂  generation would have genotypes of (Yg, and gg) and a genotypic ratio of 2:2

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3 years ago
Plants are an important part of an ecosystem
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Plants are producers
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In a population of 100 people, 30 have brown hair and 70 have black hair. What is the Relative Frequency for Black hair?
Alex

Answer:

0.7

Explanation:

Given that in statistics, the Relative Frequency is the Frequency of the class divided by Total.

Hence, in this case, the Relative Frequency of black hair is the Frequency of black hair divided by the Total.

Hence, we have 70 ÷ 100

=> 0.7

Therefore, the correct answer is 0.7 Relative frequency.

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Mechanical glad I could help!
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