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2 years ago

Given the speeds of each runner below, determine who runs the fastest.

Mathematics

2 answers:

WINSTONCH [101]2 years ago

8 0

Answer:

Brooke runs the fastest

Step-by-step explanation:

Hope this helped:)

lbvjy [14]2 years ago

3 0

Answer:

Brooke runs the fastest.

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IF 24% of the sixth grade class is in Mrs Whites class and Mrs White has 30 students how many sixth graders are there in all?

Alexeev081 [22]

Given

0.24 × (number of 6th grade students) = 30

Find

(number of 6th grade students

Solution

Divide by 0.24.

... (number of 6th grade students) = 30/0.24 = 125

4 0

3 years ago

Read 2 more answers

Alonzo, Enio, and George bought a watercolor paint box for $15.35 and 3 brushes for $2.25 each. They had a coupon for $2.00 off

Pani-rosa [81]

Answer:

Step-by-step explanation:

To solve this question we would use , 15.35+(2.25×3)−2]÷3.

Answer = C

7 0

2 years ago

A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten

AfilCa [17]

Answer:

35.11 ft

Step-by-step explanation:

This given situation can be thought of as triangle $\triangle PQR$ where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And $\angle Q \neq 90^\circ$

Given that:

PQ = 44 ft

PR = 51 ft

$\angle R = 58^\circ$

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

$\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ$

Now,

$\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ$

Let us use the Sine rule again:

$\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft$