Either way. The probability of hitting the circle is:
P(C)=Area of circle divided by area of square
P(W)=(area of square minus area of circle divided by area of square
P(C)=(πr^2)/s^2
P(W)=(s^2-πr^2)/s^2
...
Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:
P(inside circle)=π/121 (≈0.0259 or 2.6%)
P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)
Answer:
The measure of the side 
is 8.8.
Step-by-step explanation:
Since 
, then 
, 
, 
and 
. From figure we have the following relationship:
(1)
Where 
is the proportionality ratio.
If we know that 
, then the measure of side is:
(1b)
(1c)
The measure of the side is 8.8.
I’m pretty sure you would have to make them equal
1. 3x -10=7x+14
2. Add 10 to both sides
3. 3x=7x+24
4. Subtract the variable ( 7x ) from both sides
5. -4x=24
6. Divide -4/24
I hope I did it right let me know if any errors
