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netineya [11]
3 years ago
7

Given the speeds of each runner below, determine who runs the fastest.

Mathematics
2 answers:
WINSTONCH [101]3 years ago
8 0

Answer:

Brooke runs the fastest

Step-by-step explanation:

Hope this helped:)

lbvjy [14]3 years ago
3 0

Answer:

Brooke runs the fastest.

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(a²b²-c²)(a²b²+c²)<br>simplify​
liraira [26]

Answer:

a⁴b⁴ - c⁴

Step-by-step explanation:

The difference of squares formula states that (a - b)(a + b) = a² - b². In this case, a = a²b² and b = c² so a² - b² = (a²b²)² - (c²)² = a⁴b⁴ - c⁴.

6 0
3 years ago
Read 2 more answers
Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1
elena55 [62]

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

6 0
3 years ago
Write an expression to represent "triple the<br> quotient of a number and three."
Furkat [3]

Answer:

3n/3     or  3n÷3

Step-by-step explanation:

since it says triple the quotient of a <u>number</u>, we can use the number n.

To find the quotient means to divide and it's going to be by that numer.....n....... trippled (3)

put them all together and you get 3n/3

4 0
2 years ago
Write the standard form of an equation of an ellipse subject to the given conditions.
irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

\frac{x^2}{1369}+ \frac{y^2}{1394} =1

6 0
2 years ago
What is the area of the trapezoid with height 13 units? Enter your answer in the box. units2 A rectangle with a length of 15 and
jolli1 [7]

Answer:

Step-by-step explanation:

Area of the trapezoid = area of rectangle + 2 * area of triangle

Area of a triangle = 1/2 bh

= 1/2 * 13 * 7

= 45.5 units²

Area of a rectangle = L × B

= 15 × 13

= 195 units²

Area of the trapezoid = [195 + 2 * (45.5)]

= 195 + 91

= 286 units²

3 0
3 years ago
Read 2 more answers
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