Answer:
a. 300 Kg of fertilizer
b. 225 Kg of fertilizer
c. 400 Kg of fertilizer
d. 600 Kg of fertilizer
Explanation:
The percentage composition ratio of Nitrogen, Phosphorus and Potassium in a 1 Kg bag of the given fertilizer is 40:15:10.
Therefore a 1 Kg bag contains;
40/100 * 1 Kg = 0.4 Kg of Nitrogen;
15/100 * 1 Kg = 0.15 Kg of phosphorus;
10/100 * 1 Kg = 0.1 Kg of potassium
Quantity of fertilizer required to add to a hectare to supply;
a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer
b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer
c. Phosphorus at a rate of 60 kg/ha = 60/0.15 = 400 Kg of fertilizer
d. Potassium at a rate of 60 kg/ha = 60/0.1 = 600 Kg of fertilizer
Answer:
0.583 kilojoules
Explanation:
The amount of heat required to pop a single kernel can be calculated using the formula as follows:
Q = m × c × ∆T
Where;
Q = amount of heat (J)
m = mass of water (g)
c = specific heat capacity of water (4.184 J/g°C)
∆T = change in temperature
From the given information, m = 0.905 g, initial temperature (room temperature) = 21°C , final temperature = 175°C, Q = ?
Q = m × c × ∆T
Q = 0.905 × 4.184 × (175°C - 21°C)
Q = 3.786 × 154
Q = 583.044 Joules
In kilojoules i.e. we divide by 1000, the amount of heat is:
= 583.04/1000
= 0.583 kilojoules
Answer:
If 5.9 moles of CO₂ react, 5.9 moles of CuO will also react.
Explanation:
The balanced reaction is:
CuO + CO₂ → CuCO₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- CuO: 1 mole
- CO₂: 1 mole
- CuCO₃: 1 mole
You can see that the stoichiometric relationship between CuO and CO₂ is 1: 1. In other words, for each mole of CuO that reacts, one mole of CO₂ will also react.
So <u><em>if 5.9 moles of CO₂ react, 5.9 moles of CuO will also react.</em></u>
