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3 years ago

What metabolic waste accumulates in muscle with excessive exertion?

Chemistry

1 answer:

Ludmilka [50]3 years ago

4 0

Answer: Lactic acid

Explanation:

This product build up of lactic acid in the muscles engages some cellular and muscular activities leading to muscle fatigue, reduced performance and pain.

Training helps athletes to get rid of this product before it accumulate and proceed with other muscular activities.

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The most penetrating neclear radiation is

Phoenix [80]

Radioactive is the most penetrating nuclear radiation

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3 years ago

A student dilutes 50.0 mL of a 0.10 mol/L to 0.010 mol/L. Which statement is true?

VLD [36.1K]

The total amount of solute decreases.

6 0

3 years ago

In the following reaction, what is the effect on the direction of the reaction if more SO3 is added to the reaction mixture?

Stolb23 [73]

Answer:

The equilibrium shifts to produce more reactants.

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

2SO₂ + O₂ ⇄ 2SO₃

In this reaction the equilibrium is disturb by increasing the concentration of Product.

When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of SO₃ increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.

3 0

3 years ago

A liquid that evaporates at a slow rate exhibits __________.

Marizza181 [45]

Strong internolecurar forces (A) hope it helps

3 0

3 years ago

A sample of sodium-24 with an activity of 14 mCi is used to study the rate of blood flow in the circulatory system. If sodium-24

SOVA2 [1]

Answer:

See explanation

Explanation:

From;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half life of the sodium-24

t = time taken

Ao = initial activity of sodium-24

A= activity of sodium-24 at time t

0.693/15 = 2.303/15 log (14/A)

0.0462 = 0.1535 log (14/A)

0.0462/0.1535 = log (14/A)

log (14/A) = 0.0462/0.1535

14/A = Antilog(0.3)

14/A= 1.995

A = 14/1.995

A = 7.0 mCi

0.693/15 = 2.303/30 log (14/A)

0.0462 =0.0768 log(14/A)

0.0462/0.0768 =log (14/A)

(14/A) =Antilog (0.6)

A = 14/Antilog (0.6)

A = 3.5 mCi

0.693/15 = 2.303/45 log (14/A)

0.0462= 0.0512 log (14/A)

log (14/A) = 0.0462/0.0512

log (14/A) = 0.9

(14/A) = Antilog (0.9)

A= 14/Antilog (0.9)

A = 14/7.9

A = 1.77 mCi

2.5 days = 2.5 * 24 hours = 60 hours

0.693/15 = 2.303/60 log (14/A)

0.0462 = 0.03838 log (14/A)

log (14/A) = 0.0462/0.03838

(14/A) = Antilog(1.2)

A= 14/Antilog(1.2)

A = 14/15.8

A = 0.886 mCi

Note that activity (A) decreases as time increases.

5 0

3 years ago