Answer:
0.0847M is molarity of sodium hydrogen citrate in the solution
Explanation:
The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.
<em>Moles Na2C6H6O7:</em>
<em>Molar Mass:</em>
2Na: 2*22.99g/mol: 45.98g/mol
6C: 6*12.01g/mol: 72.01g/mol
6H: 6*1.008g/mol: 6.048g/mol
7O: 7*16g/mol: 112g/mol
45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol
Moles of 2g:
2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>
<em />
<em>Liters solution:</em>
100mL * (1L / 1000mL) = <em>0.100L</em>
<em>Molarity:</em>
8.473x10⁻³ moles / 0.100L =
<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
It is a solution, because it's the alloy of tin and copper
26.5 g of Fe₂(SO₄)₃
Explanation:
We have the following chemical reaction:
2 FePO₄ + 3 Na₂SO₄ → Fe₂(SO₄)₃ + 2 Na₃PO₄
number of moles = mass / molecular wight
number of moles of FePO₄ = 20 / 151 = 0.1325 moles
Taking in account the chemical reaction we devise the following reasoning:
if 2 moles of FePO₄ produces 1 mole of Fe₂(SO₄)₃
then 0.1325 moles of FePO₄ produces X moles of Fe₂(SO₄)₃
X = (0.1325 × 1) / 2 = 0.06625 moles of Fe₂(SO₄)₃
mass = number of moles × molecular wight
mass of Fe₂(SO₄)₃ = 0.06625 × 400 = 26.5 g
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number of moles
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DNA, which is found in chromosomes in the nucleus
