Answer:
This question is incomplete. The completed question is below
Procedure
1. Read and complete a lab safety form.
2. Place about 50 copper pellets into a plastic petri dish. Place the cover on the dish, and secure it with tape.
3. Hold the dish by the edges. Gently vibrate the dish from side to side no more than 1–2 mm. Observe the pellets. Record your observations in your Science Journal.
4. Repeat step 3, vibrating the dish less than 1 cm from side to side.
5. Repeat step 3, vibrating the dish 3–4 cm from side to side.
if the pellets represent particles in matter, what do you think the shaking represents?
Explanation:
This procedure seeks to illustrate the "properties" of particles in matter. The shaking of the pellets represents the movement of the particles of matter (which occurs in liquids and gases). This is because the movement of particles in a liquid and gaseous state freely moves around (reason the petri-dish was vibrated so the pellet particles which serve as the liquid/gaseous particles can move freely).
NOTE: The particles in a solid have a highly restricted movement (or no movement) because of the compact nature of the particles within the solid.
Answer:
D. 1:1
Explanation:
For every 1 mole of chlorine (Cl₂), there is one mole of calcium chloride (CaCl₂).
So, the mole ratio of chlorine to calcium chloride is 1:1.
Hope this helps. :)
<h3>
Answer:</h3>
5.89 × 10^23 molecules of F₂
<h3>
Explanation:</h3>
The equation for the reaction between fluorine (F₂) and ammonia (NH₃) is given by;
5F₂ + 2NH₃ → N₂F₄ + 6 HF
We are given 66.6 g NH₃
We are required to determine the number of fluorine molecules
<h3>Step 1: Moles of Ammonia </h3>
Moles = Mass ÷ Molar mass
Molar mass of ammonia = 17.031 g/mol
Moles of NH₃ = 66.6 g ÷ 17.031 g/mol
= 3.911 moles
<h3>Step 2: Moles of Fluorine </h3>
From the equation 5 moles of Fluorine reacts with 2 moles of ammonia
Therefore,
Moles of fluorine = Moles of Ammonia × 5/2
= 3.911 moles × 5/2
= 9.778 moles
<h3>Step 3: Number of molecules of fluorine </h3>
We know that 1 mole of a compound contains number of molecules equivalent to the Avogadro's number, 6.022 × 10^23 molecules
Therefore;
1 mole of F₂ = 6.022 × 10^23 molecules
Thus,
9.778 moles of F₂ = 9.778 moles × 6.022 × 10^23 molecules/mole
= 5.89 × 10^23 molecules
Therefore, the number of fluorine molecules needed is 5.89 × 10^23 molecules
