Answer:
Functional groups.
Explanation:
Functional groups are the specific substituents present within the molecules which are responsible for characteristic chemical properties the molecule shows.
Glucose contains alcohol and aldehyde group while hexanoic acid contains carboxylic acid group. <u>The presence different types of the functional groups in both the compounds results in the difference in the properties of both the compounds.</u>
Answer:
157.29 Torr
Explanation:
This question may be solved by the mole fraction.
Mole fraction → Moles of gas / Total moles = Partial pressure of gas / Total pressure
If the atmosphere is about 21% you assume that the mole fraction is 0.21 so:
0.21 = Partial pressure of gas / Total pressure
0.21 = Partial pressure of gas / 749 Torr
Partial pressure of the gas = 749 Torr . 0.21 → 157.29 Torr
Answer: Water is SUPER soluble and regarded as an universal solvent because it is polar in nature and dissolves most inorganic solutes and some polar organic solutes to form aqueous solutions.
Explanation:
WATER is a substance which is composed of the elements such as hydrogen and oxygen that are combined in the ratio of 2:1. The physical properties of water include:
--> it is a colourless, odourless and tasteless liquid and
--> the boiling point of water is 100°C(this is due to the presence of hydrogen bonding).
The solubility of a solute in a solvent at a particular temperature is the maximum amount of solute in moles or grams that will saturate 1000 dm³ or grams of the solvent.
Water is regarded as a universal solvent BECAUSE it is capable of dissolving many substances. This solubility helps maintain different processes in life such as acting as the solvent which helps cells transport and use substances like oxygen or nutrients.
Answer:
0,051g of O₂ are consumed
Explanation:
The reaction of precipitation of Fe(II) is:
4Fe(OH)⁺(aq) + 4OH⁻(aq) + O₂(g) + 2H₂O(l) → 4Fe(OH)₃(s)
The moles of Fe(II) you have in 85ml of 0.075 M Fe(II) are:
0,085L×0,075M = 6,4x10⁻³ moles of Fe(II)
For the reaction, you require 4 moles of Fe(II) and 1 mol of O₂(g) to precipitate the iron. Thus, moles of O₂(g) you require are:
6,4x10⁻³ moles of Fe(II)× = 1,6x10⁻³ moles of O₂(g)
These moles are:
1,6x10⁻³ moles of O₂(g)× = <em>0,051g of O₂ are consumed</em>
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I hope it helps!