let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
If you're looking for "x"
x/3 = 3
x = 3*3
x= 9
He will have 7.75 left from the 20 dollar bill he spent
Answer:
one hand comes off the bat
