We have been given that Sebastian got estimates from 7 companies for his kitchen remodel: $ 27,500 ; $31,000 ; $36,000 ; $92,000; $29,000 ; $30,500 ; $28,500. We are asked to find the best measure of center for the given data.
We can see that our given data set has a large valued data point that is $92,000.
We know that mean is very much affected by large valued outliers. The data point $92,000 will increase the mean. Therefore, mean is not a best measure of center for given data.
We know that median is very less affected by outliers, therefore, median will be best measure of center for the given data.
Answer:
The last answer is correct. (x: 1,2,3,4 ; y: -5,0,5,10)
Step-by-step explanation:
In a linear function, the rate of increase/decrease is constant (the same). For the last answer, since for every x increase, y increases by 5, it is linear and has a constant rate of change.
Answer:
3/10 of the total distance to her grandmother's house was traveled on Sunday
Step-by-step explanation:
Carly's family traveled distance of Saturday = 
Remaining distance =
They traveled 3/7 of the remaining distance on Sunday.
So, Distance traveled on Sunday =
Distance traveled on Sunday =
Fraction of the total distance to her grandmother's house was traveled on Sunday =
Hence 3/10 of the total distance to her grandmother's house was traveled on Sunday
<span>In this problem, to find the answer we have to setup a series of ratios that relate the scale to real life distance. We know that 1cm = 2.50km, so that ratio would be 1cm/2.5km. For two towns that are 4.75cm apart on the map, we set a ration of 4.75cm/x km, where x is the actual distance. Now we set the ratios equal to each other and solve for x. 1/2.5=4.75/x where x = 4.75*2.5/1 = 11.875 and rounding up we get 11.88 km. The two towns are actually 11.88 km apart from each other.</span>
