Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
You have to give us the other expressions :)
Step-by-step explanation:
We suggest, that the number 32 is 100% - because it is the output value of the task.
<span>We suggest, that x is the value that we are looking for. </span>
<span>3. If 32 is 100%, so we can jot it down as 32=100%. </span>
<span>4. We know for sure, that x is 15% of the output value, so we can jot it down as x=15%. </span>
5. Now, these are the equations are we have.
1) 32=100%
2) x=15%
where the left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
32/x=100%/15%
6. Now we just have to work out the equation, and we'll get the answer that we want.
7. Answer for what is 15% of 32
32/x=100/15
<span>(32/x)*x=(100/15)*x - </span>multiply both sides of the equation by x
<span>32=6.66666666667*x - </span>divide both sides of the equation by (6.66666666667) to get x
<span>32/6.66666666667=x </span>
<span>4.8=x </span>
x=4.8
<span>15% of 32=4.8
So, the answer is $4.8
Hope this helped</span>
