Answer: T = G - H/100
T= 12 - 12000/100 = 12 - 120 = - 105 degrees
Explanation:
T = G - H/100
T is temperature in centigrade degrees.
G is the temperature in centigrade degrees at ground level.
H is the height above ground level measured in meters.
assuming the temperature at ground level is 15 degrees centigrade, then G = 15.
the formula then becomes:
T = 15- H/100.
at ground level, H = 0 and the formula becomes 15 - 0/100 = 15 degrees centigrade.
at 100 meters, H = 100 and the formula becomes 15 - 100/100 = 15 - 1 = 14 degrees centigrade.
at 12 km above ground level, H = 12000 and the formula becomes 15 - 12000/ 100 = 15 - 120 = -105 degrees centigrade.
Answer:
Heat energy required = 687.96 kJ
Explanation:
Heat energy required, H = mCΔT.
Mass of cooking oil, m = 2.34 kg = 2340 g
Specific heat of cooking oil, C = 1.75 J/(g⋅°C)
Initial temperature = 23 °C
Final temperature = 191 °C
Change in temperature, ΔT = 191 - 23 = 168 °C
Substituting values
H = mCΔT
H = 2340 x 1.75 x 168 = 687960 J = 687.96 kJ
Heat energy required = 687.96 kJ
Based on the Newton's second law of motion, the value of the net force acting on the object is equal to the product of the mass and the acceleration due to gravity. If we let a be the acceleration due to gravity, the equation that would allow us to calculate it's value is,
W = m x a
where W is weight, m is mass, and a is acceleration. Substituting the known values,
40 kg m/s² = (10 kg) x a
Calculating for the value of a from the equation will give us an answer equal to 4.
ANSWER: 4 m/s².
Is 7.35 because you subtic them and you're get the answer
The velocity of two cars after the collision will be 6 m/sec.The momentum of the body is given by the product of the mass and velocity of the body.
<h3>What is the law of conservation of momentum?</h3>
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
According to the law of conservation of momentum
Momentum before collision =Momentum after collision
Hence, the velocity of two cars after the collision will be 6 m/sec.
To learn more about the law of conservation of momentum refer;
brainly.com/question/1113396
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