Two flat conductors are placed with their inner faces separated by 17 mm. If the surface charge density on one of the inner face

Question

4 years ago

7

s is 108 pC/m2 and the other inner face -108 pC/m2, what is the magnitude of the electric potential difference between the
two conductors?

1 answer:

blagie [28] · Answer 1 · 2021-12-24T19:06:10+03:00

4 0

Answer:

Explanation:

electric field between plates

= surface charge density / ε₀

= 108 x 10⁻¹² / 8.85 x 10⁻¹² (ε₀ = 8.85 x 10⁻¹² )

= 12.20 V/ m

Electric potential diff

= electric field x distance between plates

= 12.20 x 17 x 10⁻³ V

= 0.207 Volt