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Zigmanuir [339]
3 years ago
15

A sprinter starts from rest and accelerates to 10. m/sec in a time interval of 1.0 seconds, Calculate the runner's acceleration

Physics
1 answer:
Volgvan3 years ago
8 0

The runner's acceleration during this time interval is 10 m/s^2

<u>Given the following data:</u>

  • Initial velocity, U = 0 m/s (since the sprinter is starting from rest).
  • Final velocity, V = 10.0 m/s
  • Time, t = 1.0 seconds.

To calculate the runner's acceleration during this time interval, we would use the first equation of motion;

Mathematically, the first equation of motion is calculated by using the formula;

V = U + at

<u>Where:</u>

  • a is the acceleration.
  • V is the final velocity.
  • U is the initial velocity.
  • t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

10 = 0 + a(1)\\\\10 = a

Therefore, the runner's acceleration during this time interval is 10 m/s^2

Read more: brainly.com/question/8898885

You might be interested in
-Para lograr que una pieza de 0,300 kg de cierto metal aumente su temperatura desde 40°C a 60 °C ha sido necesario suministrarle
marishachu [46]

Answer:

parte a) el calor específico es c = 0.383 J /(gr*K)

parte b) la temperatura inicial es T inicial= 52.72 °C

Explanation:

para el primer punto la formula para el calor Q es:

Q = m * c * ( T final - T inicial )

donde

m= masa de la pieza = 0.300 kg = 300 gr

Q = flujo de energía en forma de calor= 2299 J

c = calor específico

T final = temperatura final =40°C

T inicial = temperatura inicial = 60 °C

entonces

Q = m * c * ( T final - T inicial )

c = Q / [ m* ( T final - T inicial ) = 2299 J/[ 300 gr  * ( 60 °C - 40°C )]

= 0.383 J /(gr*K)

c = 0.383 J /(gr*K)

para el segundo punto usamos la misma formula

Q = m * c * ( T final - T inicial )

pero

m= 200 gr= 0.200 kg

c=459.8 J/(kg*K) , Q =20.900 J , T final = 280 °C

Q = m * c * ( T final - T inicial )

T inicial = T final - Q/(m*c)  =280 °C - 20.900 J/(459.8 J/(kg*K)* 0.200 kg) = 52.72 °C

7 0
4 years ago
The reciprocal of frequency is
Colt1911 [192]
Frequency=1/T, where T is the time period.
Reciprocal of frequency = T or it can be written as T = 1/f, where f is frequency.
8 0
3 years ago
If the vector below is multiplied by 2, what will be its end point?
seropon [69]

The end point would be (4,-1).

<u>Explanation:</u>

When you multiply a vector with a scalar, it is known as a scalar multiplication. This multiplication is as simple as multiplying each component of the vector by the scalar because scalar is just another way to call a real number. The result of this multiplication is always a vector.

Multiplying a positive scalar larger than one will increase the magnitude of the vector, but not it's direction. A positive scalar smaller than one will decrease the magnitude. And negative scalar will reverse the direction and increase or decrease the magnitude depending on whether scalar is more than one or less than one.

6 0
3 years ago
An Eider duck is flying Northeast at 25 m/s at an angle of 36.9 degrees to the ground (from the positive
otez555 [7]

Answer:

Horizontal = 19.99212 m/s     Vertical = 15.0151 m/s

Explanation:

Horizontal = Cos(36.9) x 25

Vertical = Sin(36.9) x 25

6 0
3 years ago
Автомобиль, двигаясь равномерно, проходит третью часть пути со скоростью 20 метров в час, а остальной путь - со скоростью 36 кил
Bumek [7]

Ответ:

59,9334м / час

Пояснение:

Используя формулу Скорость = Расстояние / Время

Время = Расстояние / скорость

Если автомобиль использовал скорость 20м / час на первом этапе своего пути и преодолевает одну треть расстояния, общее время, затраченное автомобилем, составит;

Время = (д / 3) ÷ 20

Т1 = d / 3 × 1/20

T1 = d / 60 часов

Для второй части путешествия:

Если он использовал скорость 36 км / ч до конца пути

Расстояние = 1- d / 3 = 2d / 3

Скорость = 36000 м / час {1 км = 1000 м}

Время, затраченное на это путешествие = 2д / 3 ÷ 36000

Т2 = 2d / 3 × 1/36000

Т2 = 2d / 108000

T2 = d / 54000

Общее время, затраченное на всю поездку = d / 60 + d / 54000

Общее расстояние = d / 3 + 2d / 3

Общее расстояние = d

Средняя пройденная скорость за весь путь = d / (d / 60 + d / 54000)

= d / (900d + d) / 54000

= d / {901d / 54000}

= d × 54000 / 901d

= 54000/901

= 59,9334м / час

Отсюда средняя пройденная скорость за весь путь составляет 59,9334 м / час

6 0
3 years ago
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