Question

A wire of length 40 cm and area of cross -section 0.1 mm² has a resistance of 0.8Ω. Calculate specific resistance of the wire.​

Answer 1

$l = 40cm \\ \bold \red{area \: of \: cross \: section} \: a = 0.1mm {}^{2} \\ = \frac{0.1}{100} cm {}^{2} \\ \\ \R = 0.8 Ω \\ \\ \bold \green{ Specific \: Resistance \: of \: wire \:ρ } = \frac{Ra}{l} \\ = \frac{0.8}{40} \times \frac{1}{100} \\ \\ ρ = 0.00002Ω - cm$

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