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mestny [16]
3 years ago
10

Please help me guys.

Chemistry
1 answer:
Julli [10]3 years ago
4 0
It doesn’t let me see the picture it’s blurry.
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4 years ago
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3 years ago
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3 years ago
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A 0.3423 g sample of pentane, C5H12, was burned in a bomb calorimeter. The temperature of the calorimeter and the 1.000kg of wat
shtirl [24]

Answer:

Q=16.62kJ

Δ_CH=48.6kJ/g

Explanation:

Hello,

A. In this part, we must include the heat effect for pentane and water:

Q=1000gH_2O*4.184J/(g^0C)*\frac{1kJ}{1000J} *(22.82^0C-20.22^0C)+2.21kJ/^0C*(22.82^0C-20.22^0C)\\Q=16.62kJ

B. In this part, we just consider the previously computed heat and divide it by the sample of pentane as follows:

Δ_CH=\frac{Q}{m}=\frac{16.6kJ}{0.3423g}= 48.6kJ/g

Best regards.

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the general name for a substance added to a reaction that affects the rate but is not consumed in the reaction is called a_____.
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