Answer:
(1) I shifts toward product and II shifts toward reactant.
Explanation:
Increasing the temperature of an endothermic reaction (∆H is positive) shifts the equilibrium position to the right thus favoring product formation.
Increasing the temperature of an exothermic reaction (∆H is negative) shifts the equilibrium position to the left thus favoring the backward reaction.
The reaction will shift toward the products.
Adding more reactant will shift the reaction to the product.
Answer is D) <span>because you are adding positively charged protons, which pull in the outer electrons
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The radius of an atom decreases because the atomic number, or number of protons is increasing. This not only pulls in the outer electrons due to the increasing positive charge, but also increases the mass of the atom, which has the effect of drawing electrons toward the nucleus.
Answer:
they are in group II and they have two electrons in their outermost energy levels ( valency)...is this helpful?
Answer:
C
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