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Nadusha1986 [10]
3 years ago
15

In order to make 1 bike it requires 1 horn, 2 tires, and 1 chain. What would be the coefficients for the horn, tire, and chain,

assuming you wanted to make 4 bikes? Write the coefficients below!
Chemistry
1 answer:
cestrela7 [59]3 years ago
8 0
Bike is B
Horn is H
Tire is T
Chain is C

one bike would be B = H + 2T + C
you would have to multiply both sides by 4 to make 4 bikes, so then it would be
4B = 4H + 8T + 4C
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If a cube has a mass of 90.91 kilograms and a weight of 200 pounds on Earth, what will its mass and weight be on another planet?
Fudgin [204]

Answer:

The mass will be 90.91 kilograms, we can’t figure out the weight without knowing how much gravity is on the other planet.

Explanation:

Mass is the amount of substance a matter contains. The more the substance a matter contains, the more massive it becomes. The mass of an object is the same everywhere in the universe. Therefore, the cube will have the same mass of 90.91Kg in another planet.

Weight is a function of mass and the force of gravity on such a body. The weight of a body relies on the prevailing acceleration due to gravity in a particular place. Some places have gravity higher than that on earth and so they will have more weight. This is why we can't figure out weight without knowing the gravity in the other planet.

5 0
2 years ago
Consider the following reaction where Kc = 1.80×10-2 at 698 K:
Klio2033 [76]

Answer:

The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.

Explanation:

The reaction quotient Qc is a measure of the relative amount of products and reagents present in a reaction at any given time, which is calculated in a reaction that may not yet have reached equilibrium.

For the reversible reaction aA + bB⇔ cC + dD, where a, b, c and d are the stoichiometric coefficients of the balanced equation, Qc is calculated by:

Qc=\frac{[C]^{c}*[D]^{d}  } {[A]^{a}*[B]^{b}}

In this case:

Qc=\frac{[H_{2} ]*[I_{2} ] } {[HI]^{2}}

Since molarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution, you have:

  • [H_{2} ]=\frac{2.09*10^{-2} moles}{1 Liter}=2.09*10⁻² \frac{moles}{liter}
  • [I_{2} ]=\frac{4.14*10^{-2} moles}{1 Liter}=4.14*10⁻² \frac{moles}{liter}
  • [I_{2} ]=\frac{0.280 moles}{1 Liter}= 0.280 \frac{moles}{liter}

So,

Qc=\frac{2.09*10^{-2} *4.14*10^{-2}  } {0.280^{2} }

Qc= 0.011

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.

If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

Being Qc=0.011 and Kc=1.80⁻²=0.018, then Qc<Kc. <u><em>The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.</em></u>

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