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Sedaia [141]
3 years ago
7

The Doppler Effect is used at baseball games to measure ___________. @3.2.P.B5 @1

Physics
2 answers:
pentagon [3]3 years ago
8 0

Answer: The answer is A. Speed <3

Bogdan [553]3 years ago
3 0

Answer:

Explanation:

A

Those devices the hold up while the pitcher is pitching measures speed. It has nothing to do with weather and temperature.

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Which term refers to the energy that is stored or released during a change of state of water
Dima020 [189]
The appropriate term is latent heat. This energy is released as the water changes state from a gas to liquid....a liquid to solid etc. the latent heat is either absorbed or given off by the water as it changes its physical state. Latent heat of fusion is associated with freezing a liquid or melting a solid.
8 0
2 years ago
Read 2 more answers
If it requires 3.0 J of work to stretch a particular spring by 2.1 cm from its equilibrium length, how much more work will be re
-BARSIC- [3]

Answer:

Work done = 13605.44

Explanation:

Data provided in the question:

For elongation of 2.1 cm (0.021 m) work done by the spring is 3.0 J

The relation between Energy (U) and the elongation (s) is given as:

U = \frac{1}{2}kx^2   ................(1)

where,

k is the spring constant

on substituting the valeus in the above equation, we get

3.0 = \frac{1}{2}k\times0.021^2

or

k = 13605.44 N/m

now

for the elongation x = 2.1 + 4.1 = 6.2 cm = 0.062 m

using the equation 1, we have

U = \frac{1}{2}\times13605.44\times (0.062)^2

or

U = 26.149 J

Also,

Work done = change in energy

or

W = 26.149 - 3.0 = 23.149 J

4 0
2 years ago
10. A 25 kg apple cart is being pushed with an applied force of 115 N. The coefficient of friction between the ground and the ca
ziro4ka [17]

Answer:

1.1 m/s²

Explanation:

From the question,

F -mgμ = ma.................... Equation 1

Where F = applied force, m = mass of the apple cart, g = acceleration due to gravity, μ =  coefficient of friction., a = acceleration of the apple cart.

Given: F = 115 N, m = 25 kg,  μ  = 0.35

Constant: g = 10 m/s²

Substitute these values into equation 2

115-(25×10×0.35) = 25×a

115-87.5 = 25a

25a = 27.5

a = 27.5/25

a = 1.1 m/s²

8 0
3 years ago
Consider a simple pendulum with a period
lisabon 2012 [21]

Answer:

1. The length is 8.35m

2. The period on the moon is 14.05 secs

Explanation:

1. Data obtained from the question. This includes the following:

Period (T) = 5.8 secs

Acceleration due to gravity (g) = 9.8 m/s2

Length (L) =...?

The length can be obtained by using the formula given below:

T = 2π√(L/g)

5.8 = 2π√(L/9.8)

Take the square of both side

(5.8)^2 = 4π^2 x L/ 9.8

Cross multiply

4π^2 x L = (5.8)^2 x 9.8

Divide both side by 4π^2

L = (5.8)^2 x 9.8 / 4π^2

L= 8.35 m

2. Data obtained from the question. This includes the following:

Acceleration due to gravity (g) = 1.67 m/s2

Length (L) = 8.35m (the length remains the same)

Period (T) =?

The period can be obtained as follow:

T = 2π√(L/g)

T = 2π√(8.35/1.67)

T = 14.05 secs

Therefore, the period on the moon is 14.05 secs

4 0
3 years ago
Which statements describe what is occurring at t=5 seconds? Check all that apply
Alex73 [517]

Answer: The object changed directions

The object sped up

Explanation:

7 0
3 years ago
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