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3 years ago

How do scientists study pollen grains to help them understand climate change?

Physics

2 answers:

tino4ka555 [31]3 years ago

7 0

Answer: A. by analyzing and making inferences about them

Explanation:

DedPeter [7]3 years ago

3 0

Answer:

by analyzing and making inferences about them

Explanation:

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g A 475-gram ball is traveling horizontally at 12.0 m/s to the left when it is suddenly struck horizontally by a bat, causing it

AlexFokin [52]

Answer:

7.64 ms

Explanation:

3 0

3 years ago

if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height

brilliants [131]

To solve this problem we use an amplification formula for divergent lenses

$M = \frac{i}{o} = \frac{h'}{h}$

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

$M = \frac{4mm}{12mm} = \frac{h'}{18mm}$

$h'= 18mm\frac{4mm}{12mm}$

h '= 6 mm

The height is 6 mm

5 0

3 years ago

NaAlSi3O8 number of atoms persent

ad-work [718]

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

5 0

3 years ago

One anthem of silicon can properly be combined in a compound with

Darya [45]

One atom of silicon can properly be combined in a compound withtwo atoms of oxygen to produce silicon dioxide because silicon is very similar to carbon, as it is in the same group as carbon is in, therefore, it is able to make four bonds.
Moreover, Silicon has 4 valence electrons. In order to form an ionic bond, silicon<span> would have to gain or lose 4 electrons.</span>

4 0

3 years ago

A horizontal 649 N merry-go-round of radius 1.05 m is started from rest by a constant horizontal force of 61.3 N applied tangent

nexus9112 [7]

Answer:

The kinetic energy of the merry-go-round is 632.82 J

Explanation:

Given;

weight of the merry-go-round, W = 649 N

radius of the merry-go-round, r = 1.05 m

applied horizontal force, F = 61.3 N

acceleration due to gravity, g = 9.8 m/s²

mass of merry-go-round, m = W/g

= 649/9.8 = 66.225 kg

moment of inertia of merry-go-round, I = ¹/₂mr²

= ¹/₂ x 66.225 x (1.05)²

= 36.507 kg.m²

Angular acceleration of the merry-go-round, α

τ = Iα = Fr

α = Fr / I

Where;

α is angular acceleration

α = (61.3 x 1.05) / 36.507

α = 1.763 rad/s²

Angular velocity of the merry-go-round, ω

ω = αt

ω = 1.763 x 3.34

ω = 5.888 rad/s

Finally, the kinetic energy of the merry-go-round, K.E

K.E = ¹/₂Iω²

K.E = ¹/₂ x 36.507 x (5.888)²

K.E = 632.82 J

4 0

3 years ago