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brilliants [131]
3 years ago
5

This table shows experiments done by five scientists. Scientist Experiment Kyle cut a bar of gold in half Katie burned paper int

o ash Grace reacted acid and limestone together, forming carbon dioxide Isaac melted solid aluminum, forming liquid aluminum Caleb added oxygen to metal, forming rust Which three scientists have completed a chemical change? Kyle, Katie, Grace Katie, Grace, Isaac Katie, Grace, Caleb, Kyle, Isaac, Caleb
Physics
2 answers:
zvonat [6]3 years ago
5 0

Answer:

katie grace celeb

Explanation:

ik

Sladkaya [172]3 years ago
4 0

Answer:

give graph

Explanation:

we need it to answer

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State the law of conservation of linear momentum using Newton's third law of deduce this ​
MArishka [77]

Answer:

Derivation of Conservation of Momentum

Applying Newton's third law, these two impulsive forces are equal and opposite i.e. is equal to the change in momentum of the first object. is equal to the change in momentum of the second object. This relation suggests that momentum is conserved during the collision.

Explanation:

Hope it helps!!!

7 0
3 years ago
A bag of sand has a density of 45 g/cm3 and a mass of 15 kg. How much space does the sand take up?
Aleks [24]

Volume = mass/density

 

Volume = 15000 g/45 g/cm3 ≈ 333.3 cm<span>3</span>

3 0
3 years ago
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The force that pushes against something traveling through a fluid is called
olganol [36]

Viscous force is the force that pushes against something travelling through a fluid. Viscous force is an analogue in fluids(liquids or gases) of the force of friction. It acts opposite to the direction in which the object is moving relative to the fluid.

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4 years ago
Why do you think compound machines are sometimes called complex machines
Maksim231197 [3]

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i think maybe because it has more than 6 or 5 parts.

3 0
4 years ago
You pull on a crate using a rope as in (Figure 1), except the rope is at an angle of 20.0 ∘ above the horizontal. The weight of
Nezavi [6.7K]

Hi there!

For an object on an incline with friction being pulled, the following forces are present.

  • Force due to Gravity
  • Force due to Friction
  • Force due to tension

The force due to friction opposes the force due to gravity which would cause the object to slide down. (The force due to friction acts up the incline). Additionally, the force due to the rope is also upward.

Let up the incline be positive, and down the incline be negative.

Doing a summation of forces:
\Sigma F = F_T + F_f - F_g

For the crate to be moving at a constant velocity, there is NO net force acting on the crate, so:
0 = F_T + F_f - F_g

Now, we can express each force as an equation.

Force due to tension:

  • Must be solved for.

Force due to gravity:

  • On an incline, this is equivalent to the SINE component of its weight.  (Force of gravity is STILL THE WEIGHT, but on an incline, it contains a horizontal component that contributes to the net force)

This is expressed as:
F_g = Mgsin\theta

Force due to friction:

  • Equivalent to the normal force and coefficient of friction. The normal force is the VERTICAL component of the object's weight, so:

N = Mgcos\theta

F_f = \mu Mgcos\theta

Now, plug these expressions into the above equation.

0 = F_T + \mu Mgcos\theta - Mgsin\theta\\\\Mgsin\theta - \mu Mgcos\theta = F_T

Mg = 245 N (weight). Plug in all values:
245sin(20) - 0.270(245)cos(20) = F_T\\\\F_T = \boxed{21.634 N}

The normal force is equivalent to the vertical component (PERPENDICULAR TO THE INCLINE) of the weight (cosine), so:

N = Mgcos\theta\\\\N = 245cos(20) = \boxed{230.225 N}

5 0
2 years ago
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