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Alex17521 [72]
3 years ago
15

Give an example of a real number, an imaginary number, and a complex number. Use examples that have not

Mathematics
1 answer:
irinina [24]3 years ago
6 0

Answer:

Real number 5

Imaginary number 5i

Complex number 2+5i

Step-by-step explanation:

A real number is that number that can be represented on number line

There is no imaginary part in real number

Example of real number is 5

Imaginary number is that in which there is no real part

Example of imaginary number is 5i

When there is a combination of both real and imaginary part then number is called complex number

Example of complex number is 2+5i

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coldgirl [10]

Answer:

thanks

Step-by-step explanation:

I have been patient trying to get a job

6 0
3 years ago
Sally is standing at one corner of a snowy rectangular field that measures 200 ft by 200 ft. She wishes toreach a warm cabin loc
pshichka [43]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The optimal point(i.e the position of  P) that will allow Sally to reach the cabin as quickly as possible is  d =  50 \ ft from the cabin.

Step-by-step explanation:

From the question we are told that

   The speed from the point Sally is standing to the point P is  u =  3 \  ft /s

   The speed from the point P to the cabin is v  =  5 \  ft /s

   

Let denote the distance from the bottom left corner to the  P  be  y  ft

 Generally according to Pythagoras theorem the distance from Sally's first position to point P is mathematically represented as

          s = \sqrt{y^2 + 200^2}

Generally the distance from that point P to the cabin is mathematically represented as

       d =  200 -y

Generally the time it takes Sally to cover that distance s is mathematically represented as

       t_1 =  \frac{s}{u}

=>     t_1 =  \frac{ \sqrt{y^2 + 200^2}}{3}

Generally the time it takes Sally to cover that distance d is mathematically represented as

       t_2 =  \frac{d}{v}

=>     t_2 =  \frac{ 200 - y }{5}

So the total time taken is  

        t= \frac{ \sqrt{y^2 + 200^2}}{3}  +  \frac{ 200 - y }{5}

Generally the minimum time taken with respect to the distance is mathematically evaluated by differentiating and equating the derivative to 0

So  

     \frac{dt}{dy} =\frac{1}{3} \frac{y}{ \sqrt{y^2 + 200^2} }  -  \frac{1}{5}  =0      

=> \frac{dt}{dy} = \frac{y^2 }{y^2 + 200 ^2} =\frac{9}{25}

=> 25y^2 = 9y^2 + 9 * 200^2        

=> 16y^2 = 360000          

=> y = 150

So the distance from point P to the cabin is  

           d =  200 -150

=>       d =  50 \ ft

So  the optimal point(i.e the position of  P) that will allow Sally to reach the cabin as quickly as possible is  d =  50 \ ft from the cabin

       

8 0
3 years ago
Help me please not tryna fail !
sp2606 [1]

Answer:

x=27

∠JLK=2x+1=2(27)+1=55

Step-by-step explanation:

∠A+∠K=180

3x+13+∠K=180

∠K=167-3x

∠K+∠L+∠J=180

167-3x+39+2x+1=180

207-x=180

x=27

∠JLK=2x+1=2(27)+1=55

Don't worry, you aren't gonna fail. Take a deep breath and relax. Geometry is tricky but you got this. Have a nice night.

7 0
3 years ago
Read 2 more answers
Create an example of a situation where there is a negative cash flow.
dimaraw [331]

Answer:

when say your expenses are $400 a month but your income is only $350 a month that is -$50 every month so in that case you aren't getting a positive cash flow (which would be making more money than your expenses) So you must be getting a negative cash flow in which you are losing money and going into debt.

Hope this Helps :)

6 0
3 years ago
5 x 10 - 2 = ??<br> HALP MOIIIIIIIIIIIIIIIIIIIIII
solmaris [256]

Answer:

48

Step-by-step explanation:

the answer is 48 I got this answer by multiplying 5 by 10 and subtracting is from 2 which gives me 50 - 2 which is 48

5 0
3 years ago
Read 2 more answers
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