Find the simplified product 3 sqrt9x^4 times 3sqrt3x^8

Mathematics

2 answers:

lord [1]2 years ago

8 0

Answer:

latex?

Step-by-step explanation:

stepan [7]2 years ago

3 0

[tex]\bf is the answer.

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Angelina_Jolie [31]

You can rewrite the second equation because you know what y equals, so you can write it as 2x + x + 3 = 9
3x + 3 = 9
- 3
3x = 6
÷ 3
x = 2

And now you use the equation of what y equals and substitute in the value of x, so y = 2 + 3
y = 5

So your final answer is A. (2, 5). I hope this helps!

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Is it necessary to rename 4 1/4 if you subtract 3/4 from it

Nesterboy [21]

No because they both have the same denominator!

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lara [203]

$\frac{3}{2};\ \frac{3}{4};\ \frac{3}{8};\ \frac{3}{16};\ ...\\\\a_1=\frac{3}{2}\\\\a_2=\frac{3}{4}=\frac{3}{2}\cdot\frac{1}{2}\\\\a_3=\frac{3}{8}=\frac{3}{4}\cdot\frac{1}{2}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^2\\\\a_4=\frac{3}{16}=\frac{3}{8}\cdot\frac{1}{2}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^3\\\vdots$
$a_n=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{n-1}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{-1}\cdot\left(\frac{1}{2}\right)^n=\frac{3}{2}\cdot2\cdot\left(\frac{1}{2}\right)^n=3\cdot\left(\frac{1}{2}\right)^n$

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Answer:

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Step-by-step explanation:

If for each hour is $10.

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