Question

A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white. A child randomly pulls 4 marbles from the bag. What is the probability that the marbles chosen are green, blue, red, and yellow? Round your answer to the nearest hundredth.

Answer 1

Answer:

Probability of getting green, blue, red, and yellow = 0.69

Step-by-step explanation:

Given - A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white. A child randomly pulls 4 marbles from the bag.

To find - What is the probability that the marbles chosen are green, blue, red, and yellow?

Proof -

Given that,

A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white.

i.e.

All the outcomes are equally likely.

So,

The child can choose the 4 marbles in 4! ways.

And

Total number of ways = $^{7} C_{4}$ = 35

So,

Probability of getting green, blue, red, and yellow = $\frac{4!}{35}$

                                                                                   = $\frac{24}{35}$ = 0.69

⇒Probability of getting green, blue, red, and yellow = 0.69