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gizmo_the_mogwai [7]
3 years ago
14

Simplified to create an equivalent expression (2+2w)•4+9(w+3)=

Mathematics
1 answer:
ahrayia [7]3 years ago
5 0

Answer:

17 w  +  35

Step-by-step explanation:

You get this answer by using PEMDAS.

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There are 4,389 dogwood trees in the state park. The park workers are going to plant 342 more trees. How many trees will there b
Dmitrij [34]

Answer:

4731

Step-by-step explanation:

4,389+342=4,731

6 0
3 years ago
Which two equations would be represented as parallel lines?
Mariana [72]

Answer:

The first and third options are parallel.

Step-by-step explanation:

They both have a slope of 2.

Pls mark brainliest. Thanks!

4 0
3 years ago
Read 2 more answers
Which expression can be used to find the surface area of the following triangular prism?
Orlov [11]

Answer:

214.

Step-by-step explanation:

To get Surface area take

(cross section area) × 2 +(perimeter of crossection area × length)

the cross section area is a triangle

so area of a triangle =1/2 base times height

1/2×8×2=8

let's get perimeter of cross section

the cross section is still at triangle so let's find its perimeter.

5+5+8=18

18×length of which is 11

18×11=198

and 188 + 16=214. that's the answer

maybe you can get a expression from the work that I've just done cuz I can't see the answers clearly in the picture you have taken.if you don't mind just send the picture back then I'll get the answer.

6 0
2 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
Please help me with my math homework
Alborosie
I'm sorry but your photo doesn't really show the whole paragraph clearly so I can't answer
6 0
3 years ago
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