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ki77a [65]
3 years ago
7

63 is 63% of what number​

Mathematics
2 answers:
PIT_PIT [208]3 years ago
6 0
63 / 0.63 = 100
Answer: 100
san4es73 [151]3 years ago
5 0
63 is only 63% of the number 100.
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$800 at 3.8% interest for 6 months<br> What is the interest?<br><br> What is the new balance?
Furkat [3]
Use the equation I/PT = R I is the interest P is the money before investment and T is the time
4 0
3 years ago
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12 1/2 - (-4 1/2) =​
puteri [66]

Answer: the answer here is 8

Step-by-step explanation:

just lay it out up to down, divide annnnnd SHABLAM you got the answer :)

3 0
3 years ago
Walter bought 500 marbles at the swap meet. Two-fifths of them
MrRissso [65]

Step-by-step explanation:

2/5 of marbles are blue

= 3/5 of marble are not blue.

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300 marbles are not blue.

4 0
2 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
The graph shows the location of point P and point R. Point R is on the y-axis and has the same y-coordinate as point P. Point Q
Mumz [18]

Answer:

n = 5

Step-by-step explanation:

Coordinate of P = (n,3)

R is on y-axis & the y-coordinate of P & R are equal. So coordinate of R = (3,0)

Coordinate of Q = (n,-2)

Using distance formula,

Distance between P & Q =

\sqrt{ {( n  -  n}) ^{2} +  {( 3-  ( - 2)  })^{2}   }

=  >  \sqrt{ {(3 + 2)}^{2} }  =  \sqrt{ {5}^{2} }  = 5

Distance between P & R =

\sqrt{ {(n - 0)}^{2} +  {(3 - 3)}^{2}  }

=  >  \sqrt{ {n}^{2} }  = n

But in question it is given that distance between P & Q is equal to the distance between P & R. So,

n = 5

8 0
2 years ago
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