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natta225 [31]
3 years ago
9

Kyle anticipates that he will be in a higher tax bracket when he retires than he's in now.

Mathematics
1 answer:
kupik [55]3 years ago
3 0

Answer:

For Kyle, a Roth IRA would be a better choice if he wants to pay less tax, since the tax will be collected when he contributes funds.

Explanation:

If kyle falls in higher tax bracket when he retires, then Roth IRA is the best option.Roth IRA is an individual's retirement saving account that offers valuable tax benefits, that is the money invested within the Roth IRA is tax free and withdrawal in retirement will be tax free too.That is you contribute money now that you'll pay income taxes on this year, but the withdrawal will be tax free during retirement.

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If g(x) is a linear function such that g(-3) = 2 and g(1) = -4, find g(7).
eimsori [14]
<h3>Answer:   -13</h3>

=======================================

Explanation:

g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)

g(1) = -4 means we have the point (1,-4)

Find the slope of the line through the two points (-3,2) and (1,-4)

m = (y2-y1)/(x2-x1)

m = (-4-2)/(1-(-3))

m = (-4-2)/(1+3)

m = -6/4

m = -3/2

m = -1.5

The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5

Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation:  2 = -1.5*(-3) + b

Let's solve for b

2 = -1.5*(-3)+b

2 = 4.5 + b

2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides

-2.5 = b

b = -2.5

Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5

The last step is to plug in x = 7 and compute

g(x) = -1.5*x - 2.5

g(7) = -1.5*7 - 2.5

g(7) = -10.5 - 2.5

g(7) = -13

6 0
3 years ago
Read 2 more answers
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
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If John has an apple, an orange, a pear, a banana, and a kiwi at home and he wants to bring two fruits for lunch, how many diffe
SVEN [57.7K]

Answer:

10

Step-by-step explanation:

5 choose 2 is 5x4/2, which is 20/2, which is 10.

5 0
3 years ago
Max can type 160 words in 5 minutes.
Lelechka [254]
400/160=2.5          This is finding the necessary multiplier
2.5*5=x                 I used 2.5 and multiplied it by 5
x=12.5 minutes      This is the answer

It would take 12 minutes and 30 seconds
5 0
3 years ago
Read 2 more answers
what would it be if the sum of six consecutive even numbers is 130 what would the 2nd number be in the sequence PLZ HELP
zubka84 [21]

Answer:

\huge\boxed{Second\ Number = 42}

Step-by-step explanation:

Let the consecutive even numbers be x,x+2,x+4, x+ 6, x+ 8 and x+10

So, the given condition is:

x+x+2+x+4+x+6+x+8+x+10 = 270

6x + 30 = 270

Subtracting both sides by 30

6x = 270 - 30

6x = 240

Dividing both sides by 6

x = 40

So,

First Number = x = 40

Second Number = x+2 = 40+2 = 42

Third Number = x+4 = 40+4 = 44

Fourth Number = x+6 = 40+6 = 46

Fifth Number = x+8 = 40+8 = 48

Sixth Number = x+10 = 40+10 = 50

4 0
3 years ago
Read 2 more answers
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