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alexandr402 [8]
3 years ago
7

Plese i need help on this one !!!!!!!

Mathematics
3 answers:
patriot [66]3 years ago
8 0

Answer:

I got 32.

Step-by-step explanation:

I used the Pythagorean theorem to find the lengths of the width and length. The length between (-1, 4) and (3, 3) was approximately 4 in. The distance between (-1, 4) and (-3, -4) was approximately 8 in. I then used those numbers to find the perimeter ((2*4)+(2*8))

astra-53 [7]3 years ago
5 0

Answer:

I got 32.

Step-by-step explanation:

I used the Pythagorean theorem to find the lengths of the width and length. The length between (-1, 4) and (3, 3) was approximately 4 in. The distance between (-1, 4) and (-3, -4) was approximately 8 in. I then used those numbers to find the perimeter ((2*4)+(2*8))

sveta [45]3 years ago
5 0

Answer:

I got 32.

Step-by-step explanation:

I used the Pythagorean theorem to find the lengths of the width and length. The length between (-1, 4) and (3, 3) was approximately 4 in. The distance between (-1, 4) and (-3, -4) was approximately 8 in. I then used those numbers to find the perimeter ((2*4)+(2*8))

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
stepan [7]

Answer:

hola:)

Step-by-step explanation:

3 ^6= 6x6x6

4 ^5= 4x4x4x4x4

6 ^3=3x3x3x3x3x3

5 ^4= 4x4x4x4x4

8 0
3 years ago
(03.02)
777dan777 [17]

Answer:

To provide a situation of 1 and O, here is a situation

Step-by-step explanation:

The acceleration would be 1.  

If the acceleration is 10 m/s, the object will gain more speed.

On the other hand, if the acceleration is -10m/s, then the object will lose speed.

In the case of 1, the object gained more speed, in the case of 0, the object will lose speed.

4 0
3 years ago
Plz help me well mark brainliest if correct.....<br><br><br> .......????
Gemiola [76]

Answer:

C) The mean is about 100.

Step-by-step explanation:

We see that the best fit line (out of the options listed) would be y=100. The mean can also be algebraically calculated with the following equation:

Let a be the mean (average) of the values:

a=\frac{75+50+100+125+75+150}{6}=95.8\overline{3}, which is closest to answer choice C) The mean is about 100.

3 0
2 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
1 year ago
In a​ state's Pick 3 lottery​ game, you pay ​$1.15 to select a sequence of three digits​ (from 0 to​ 9), such as 966. If you sel
m_a_m_a [10]

Answer:

A) 1000 different selections

B) probability of winning = 0.001

C) Net profit on winning = $257.20

D) E(y) = -0. 89165

E) Option B - The Pick 4 game is a better bet because it has a larger expected value.

Step-by-step explanation:

A) For the different selections possible, since each of the digits from 0 - 9 can take a total of 10 digits, then the different selections possible will be = 10³ = 1000 different selections

B) To find the probability of winning, since only one pick can be a winning one. Thus probability of winning = 1/1000 = 0.001

C) Net profit on winning = Amount won - Amount staked

Amount won = ​$258.35

Amount staked = ​$1.15

Thus;

Net profit on winning = ​$258.35 - ​$1.15

Net profit on winning = $257.20

D) If we call the net profit "y", then Expected value is:

E(y) = 257.2(0.001) - 1.15(1 - 0.001)

E(y) = 0.2572 - 1.14885

E(y) = -0. 89165

E) We are told that:If you bet $ 1.15 in a certain​ state's Pick 4​ game, the expected value is negative −$0.89

The expected value of -0.89 in pick 4 is better than that in pick 3 because it's larger.

6 0
3 years ago
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