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Rus_ich [418]
3 years ago
6

Towns P,Q,R and S are shown. Q is 35 km due East of P S is 15km due West of P R is 15km due South of P Work out the bearing of R

from S? Work out the bearing from R to Q?
Mathematics
1 answer:
Anni [7]3 years ago
6 0

Answer:

Part A

The bearing of the point 'R' from 'S' is 225°

Part B

The bearing from R to Q is approximately 293.2°

Step-by-step explanation:

The location of the point 'Q' = 35 km due East of P

The location of the point 'S' = 15 km due West of P

The location of the 'R' = 15 km due south of 'P'

Part A

To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that \overline{RP} = \overline{SP}, the right triangle ΔRPS is an isosceles right triangle

∴ ∠PRS = ∠PSR = 45°

The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°

Part B

∠PRQ = arctan(35/15) ≈ 66.8°

Therefore the bearing  from R to Q = 270 + 90 - 66.8 ≈ 293.2°

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Answer:

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<h3>x =  \frac{ - 5 +  \sqrt{13} }{6}  \:  \:  \:  \: or \:  \:  \: x  =  \frac{ - 5 -  \sqrt{13} }{6}</h3>

Step-by-step explanation:

2x² = - x² - 5x - 1

<u>Rearrange the terms and simplify</u>

That's

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