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Harrizon [31]
2 years ago
7

Which value is equivalent to​

Mathematics
1 answer:
mezya [45]2 years ago
4 0
7^2 I think is the write answer
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This table shows numbers of sweets in some tubes, but a coffee stain has deleted one of the figures.
svlad2 [7]
To get the answer, you need to think of it like a see-saw.
Both sides must equal the same relative to 33.5. For example, 32 is 1.5 away from 33.5 so you could say you have 1.5*4 (because theres 4 tubes with 32 sweets). If you were to do this for the whole table, it would look something like this:

(1.5*4)+(0.5*x)=(0.5*9)+(1.5*1)+(2.5*1)

This simplifies to:

6+0.5x=8.5
0.5x=2.5
x= \frac{2.5}{0.5}
x=5

This method can sometimes be inefficient depending on how many values but is probably the simplest way to solve this problem.

hope this helps :)

(sorry the other way is kinda hard to explain possibly ask your teacher tomorrow)
6 0
2 years ago
What would the world be like without math or money? why
Phantasy [73]
Everyone would be confused because they wouldnt know how to add. if there wasnt money then there with be no objects/food/toys/ect. unless its all free. If it all free then everyone would go crazy because they wouldnt have to calculate how much the item cost.
8 0
3 years ago
Read 2 more answers
Y-2=4(x+3) what the slope intercept
Kryger [21]

Answer:

Slope intercept form: y = 4x + 14

Slope: 4

Y-intercept: 14

Step-by-step explanation:

y - 2 = 4(x + 3)

Use distributive property

y - 2 = 4x + 12

y - 2 + 2 = 4x + 12 + 2

y - 0 = 4x + 14

y = 4x + 14

3 0
2 years ago
A business has $15,000 to spend on airline tickets to travel to a conference. It wants 27 of its employees to attend. The busine
VikaD [51]
In order to get as many tickets they need 15 business class tickets and 12 economy class tickets (700x15=10,500)(375x12=4500) Which when you add those two makes 15,000.
4 0
3 years ago
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which of the following statements about perpendicular lines is true? a. perpendicular lines have a constant distance between the
Flauer [41]
B is the right answer
7 0
3 years ago
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