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Elodia [21]
3 years ago
6

Hi help me please or do something i dont know

Mathematics
2 answers:
Levart [38]3 years ago
5 0

Answer:

To know the y values in of both the tables I have

y=2.25x.

To get the equation y=2.25x, I need to get the value of y divide by the value of x, repeat this process for both of the tables. You can see that they are all proportional to each other.

For the first table we have:

360÷160=2.25, 1125÷500=2.25, 2700÷1200=2.25

In order to form a equation they all have to have the same proportion.

Then, there you have it.

y=2.25x

For the second table we have:

4.5÷2=2.25, 11.25÷5=2.25, 15.75=2.25

y=2.25x

to check if the equation is right

y=2.25(160)=360 (for the first table)

y=2.25(500)=1125

y=2.25(1200)=2700

Goryan [66]3 years ago
4 0

Answer:

y=2.25x.

Step-by-step explanation:

You might be interested in
Simplify 12/2 . 12/3
V125BC [204]

Step-by-step explanation:

is that really all ?

to simplify 12/2 and 12/3 ?

well, 12 can be divided by 2 and by 3 without remainder.

and so we get

12/2 = 6/1 = 6

12/3 = 4/1 = 4

8 0
3 years ago
The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
3 years ago
Which two points lie on the circumference of this circle? A. (1.3,0.5) B. (2.5,1.5) C. (3.4, -0.2) D. (3.9,0.7) E. (6.0,-2.0)
liq [111]

Step-by-step explanation:

(x-2)²+(y+5)²=25

option C (3.4,-0.2)

LHS= (3.4-2)²+(-0.2+5)²

= (1.4)²+(4.8)²

= 1.96+23.04

= 25

option E(6,-2)

LHS= (6-2)²+(-2+5)² = 4²+(-3)² = 16+9 = 25

6 0
3 years ago
-4,4 reflected in the y axis
matrenka [14]
-4,4 reflected in the y axis is 4,4
5 0
3 years ago
Please help me with this, I will give brainliest.
defon

Answer:

5.9 or 5.85 unrounded

8 0
2 years ago
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