Answer:
Cp = 0.093 J.g⁻¹.°C⁻¹
Solution:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 300 J
m = mass = 267 g
Cp = Specific Heat Capacity = ??
ΔT = Change in Temperature = 12 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 300 J / (267 g × 12 °C)
Cp = 0.093 J.g⁻¹.°C⁻¹
To calculate how many photons are in a certain amount of energy (joules) we need to know how much energy is in one photon.
Start by using two equations:
Energy of a photon = Frequency * Planck's constant (6.626 * 10^(-34) J-s)
Speed of light (constant 3 * 10^8 m/s) = Frequency * Wavelength
Which means:
frequency = Speed of Light / Wavelength
So energy of a photon = (Speed of light * Planck's constant)/(Wavelength)
You may have seen this equation as E = hc/<span>λ</span>
We have a wavelength of 691 nm or 691 * 10^-9 meters
So we can plug in all of our knowns:
E = (6.626 * 10^(-34) J-s) * (3.00 * 10^8 m/s) / (691 * 10^-9 m) =
2.88 * 10^(-19) joules per photon
Now we have joules per photon, and the total number of joules (0.862 joules)
,so divide joules by joules per photon, and we have the number of photons:
0.862 J/ (2.88 * 10^(-19) J/photon) = 3.00 * 10^18 photons.
Answer:
I'm pretty sure its the one that says very little at the beginning but if I get it wrong I'm sorry
<u>Answer:</u> The products of the reaction will be ![I_2\text{ and }KBr](https://tex.z-dn.net/?f=I_2%5Ctext%7B%20and%20%7DKBr)
<u>Explanation:</u>
Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The general chemical equation for the single displacement reaction follows:
![A+BC\rightarrow AC+B](https://tex.z-dn.net/?f=A%2BBC%5Crightarrow%20AC%2BB)
The given chemical equation follows:
![Br_2+2KI\rightarrow I_2+2KBr](https://tex.z-dn.net/?f=Br_2%2B2KI%5Crightarrow%20I_2%2B2KBr)
Bromine element is more reactive than iodine element. Thus, can easily replace iodine from its chemical reaction.
Hence, the products of the reaction will be ![I_2\text{ and }KBr](https://tex.z-dn.net/?f=I_2%5Ctext%7B%20and%20%7DKBr)