What is the slope of the line shown below?

Write Y=5/3 x - 6/8 in standard form

ratelena [41]

Answer:

standard form is Ax + By = C where A, B and C are all integers.

y=5/3x-6/8 First, multiply by LCD 24:

24y = 40x -18

40x - 24y = 18

Division by 2 is recommended (this is because 6/8 should have been reduced to 24, making LCD just 12):

20x - 12y = 9

Step-by-step explanation:

3 0

4 years ago

A triangle with equal sides and a square have the same perimeters. The length of a side of the triangle is 2x + 2. The length of

andreev551 [17]

Answer:

x=13

Step-by-step explanation:

$3(2x+2)=4(x+8)\\6x+6=4x+32\\2x+6=32\\2x=26\\x=13$

3 0

4 years ago

The length of the classroom is 36 feet.

murzikaleks [220]

35 x 25 = 875 square ft

6 0

3 years ago

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The image of parallelogram PQRS after a reflection across Line W Y is parallelogram P'Q'R'S'.

Luden [163]

Answer:

the answer is 6

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Tim claims that a coin is coming up tails less than half of the time. In 110 tosses, the coin comes up tails 47 times. Using P-v

lilavasa [31]

Answer:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=47 represent the number of tails obtained

$\hat p=\frac{47}{110}=0.427$ estimated proportion of tails

$p_o=0.5$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of tails is lower than 0.5:

Null hypothesis: $p\geq 0.5$

Alternative hypothesis: $p < 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

6 0

3 years ago