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3 years ago

What is the slope of the line shown below?

Mathematics

1 answer:

IrinaVladis [17]3 years ago

3 0

Answer:

D. 7/3

Explanation:

Y1 - Y2 / X1 - X2

9 - -5 / 6 - 0

9 + 5 / 6

14 / 6

7/3

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Write the expression below as a product of two factors.<br> -12p + 6y - 24

MariettaO [177]

Answer:

− 6 ( 2 p − y + 4 )

Step-by-step explanation:

5 0

2 years ago

A man is 13 times as old as his son is. In 10 years he will be 3 times as old as his son is now. How old are they now?

valkas [14]

Answer:

the son is 2

man is 26

+10 yrs

son=12

man=36

Step-by-step explanation:

Let the son's age be x.

Then the father's age is 13x.

In ten years their ages will be (x+10) and (13x+10).

(13x+10)=3(x+10)

13x+10=3x+30

10x=20

x=2

The son is 2 years old.

3 0

2 years ago

Given sin x = -4/5 and x is in quadrant 3, what is the value of tan x/2

love history [14]

bearing in mind that, on the III Quadrant, sine as well as cosine are both negative, and that hypotenuse is never negative, so, if the sine is -4/5, the negative number must be the numerator, so sin(x) = (-4)/5.

$\bf sin(x)=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2-(-4)^2}=a\implies \pm\sqrt{9}=a\implies \pm 3=a \\\\\\ \stackrel{III~Quadrant}{-3=a}~\hfill cos(x)=\cfrac{\stackrel{adjacent}{-3}}{\stackrel{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill$

$\bf tan\left(\cfrac{\theta}{2}\right)= \begin{cases} \pm \sqrt{\cfrac{1-cos(\theta)}{1+cos(\theta)}} \\\\ \cfrac{sin(\theta)}{1+cos(\theta)}\qquad \leftarrow \textit{let's use this one} \\\\ \cfrac{1-cos(\theta)}{sin(\theta)} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{1-\frac{3}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{\frac{2}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{5}\cdot \cfrac{5}{2} \\\\\\ tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{2}\cdot \cfrac{5}{5}\implies tan\left( \cfrac{x}{2} \right)=-2$

4 0

3 years ago

Read 2 more answers

Find the perimeter of the triangle defined by the coordinates (9, 0), (-5, 0), and (-10, 6). (Round to nearest tenth)

eduard

The perimeter is 41.7.

We first find the distance between each vertex using the distance formula:
$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}
\\
\\=\sqrt{(0-0)^2+(-5-9)^2}=\sqrt{0^2+(-14)^2}=\sqrt{196}=14
\\
\\d=\sqrt{(6-0)^2+(-10--5)^2}=\sqrt{6^2+(-5)^2}=\sqrt{36+25}=\sqrt{61}
\\=7.81
\\
\\d=\sqrt{(6-0)^2+(-10-9)^2}=\sqrt{6^2+(-19)^2}=\sqrt{36+361}=\sqrt{397}
\\=19.92$

We now find the perimeter by adding all of the side lengths:
14+7.81+19.92 = 41.73 ≈ 41.7

7 0

3 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

Citrus2011 [14]

Answer:

a) Line M

b)Line M

c)y=1/2x+2

Step-by-step explanation:

a) Line M has a greater y-intercept since its y-intercept is at (0,2) while Line N's y-intercept is at (0,1)

b) Line M has a greater slope since its line is steeper

c) Use the formula y=mx+b

Use the points ( 0,1) and (-4,-1)

m(slope)= y2-y1/x2-x1

m= (-1-1)/(-4-0)

m=-2/-4

m=1/2

substitute

(0)=1/2(-4)+b

2=b(y-intercept)

y=1/2x+2

3 0

2 years ago

Read 2 more answers