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Digiron [165]
3 years ago
15

The two properties that are parts of refraction are ...

Physics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

-Relative refractive index– It is the ratio of speed of light in one medium to the speed of light in another medium

-Absolute refractive index– It is the ratio of light in vacuum to the speed of light in another medium.

Explanation:

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Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point
Salsk061 [2.6K]

Answer:

The fluids speed at a) 0.105\,m^{2}  and b) 0.047\,m^{2} are 2.33\,\frac{m}{s^{2}}  and 5.21\,\frac{m}{s^{2}} respectively

c) Th volume of water the pipe discharges is: 882\,m^{3}  

Explanation:

To solve a) and b) we should use flow continuity for ideal fluids:

\Delta Q=0(1)

With Q the flux of water, but Q is Av using this on (1) we have:

A_{2}v_{2}-A_{1}v_{1}=0 (2)

With A the cross sectional areas and v the velocities of the fluid.

a) Here, we use that point 2 has a cross-sectional area equal to A_{2}=0.105\,m^{2}, so now we can solve (2) for v_{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.105}\approx2.33\,\frac{m}{s^{2}}

b) Here we use point 2 as A_{2}=0.047\,m^{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.047}\approx5.21\,\frac{m}{s^{2}}

c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is Q=\frac{V}{t}, so we can write:

A_{1}v_{1}=\frac{V}{t}, solving for V:

V=A_{1}v_{1}t=(0.070m^{2})(3.5\frac{m}{s})(3600s)=882\,m^{3}

3 0
4 years ago
Which of the following keys moves the insertion point to the beginning of data in a cell? (Points : 2)
Korvikt [17]
Insert moves the insertion point to the beginning of data in a cell so the answer is INSERT :)))
i hope this be helpful
6 0
3 years ago
An atom with 6 protons and 5 electrons would be what kind of atom?
dybincka [34]

cation

anion is negatively charged, so more electrons then protons,

cation is positively charged, so more protons thatn electrons

4 0
3 years ago
Read 2 more answers
Power of sunlight on Earth The Sun emits about 3.9 * 1026 J of electromagnetic radiation each second. (a) Estimate the power tha
ratelena [41]

Answer:

a)6.34 x  10^{7}W/m²

b)1.37 x 10^{3 W/m²

c) see explanation.

Explanation:

a)The relation of intensity'I' of the radiation and area 'A' is given by:

I= P/A

where P= power of sunlight i.e 3.9 x 10^{26} J

and the area of the sun is given by,

A= 4πR_{sun} => 4π(\frac{1.4*10^{9} }{2} )^{2}

A=6.15 x 10^{18}m²

I_{sun} =  3.9 x 10^{26} / 6.15 x 10^{18} =><u> 6.34 x  </u>10^{7}<u>W/m²</u>

b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space

A= 4πR

Now R= 1.5 x 10^{11m

A=  4π x 1.5 x 10^{11 =>2.83 x 10^{23 m²

The power that each square meter of Earths surface receives

I_{earth =   3.9 x 10^{26}/2.83 x 10^{23 =><u>1.37 x </u>10^{3<u> W/m²</u>

<u />

c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.

6 0
3 years ago
A car moving on a straight level road changes its speed from 3.5m/s to 4.5m/s in 5.00 seconds. Find it’s acceleration
mixer [17]

Answer:

0.2m/s2

Explanation:

acceleration= change in velocity ( in this case speed)/ change in time.

4.5-3.5=1m/s

change in time=5-0 =5

1m/s divided by 5 seconds acceleration as the result

8 0
3 years ago
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