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4 years ago

A scientist wants to test ways to reduce pollution in lake . What is the bestway of doing this

Physics

2 answers:

siniylev [52]4 years ago

7 0

Clean it up hope it's right have a good day

JulijaS [17]4 years ago

6 0

i would think by taking all the water out and storing it somewhere else and filtering it or cleaning it then put it back

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A compressed spring is compressed between a 5kg and 3 kg cart, respectively. When the spring is released, what will be the same

stira [4]

The momentum of the two carts will be the same

Explanation:

First of all, we notice that the system consisting of the two carts + the spring is an isolated system: this means that there are no external forces acting on it.

As a result, the total momentum of the system must be conserved.

Since the spring is at rest, the total momentum of the system after the two carts are released is:

$p_f = p_1 + p_2$

where

$p_1$ is the momentum of the 1st cart

$p_2$ is the momentum of the 2nd cart

The total momentum of the system at the beginning, when the spring is compressed, is zero:

$p_i=0$

Since the total momentum must be conserved, we have:

$p_i = p_f\\0 = p_1 + p_2\\\rightarrow p_2 = -p_1$

Which means that the two carts will have equal and opposite momenta.

Learn more about momentum:

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4 0

3 years ago

What is the difference between luxury and a necessity

myrzilka [38]

Luxury is an antonym of necessity. Necessity is an antonym of luxury.
As nouns the difference between necessity and luxury is that necessity is the quality or state of being necessary, unavoidable, or absolutely requisite while luxury is very wealthy and comfortable surroundings.

7 0

3 years ago

A railroad track and a road cross at right angle. An observer stands on the road 70 meters south of the crossing and watches an

fgiga [73]

Answer:

The train is moving with a speed of 57.6 m/s.

Explanation:

Given that,

Distance of observer from the road, d = 40 m (due south)

Velocity of the train, v = 60 m/s (due east)

So,

$x(t)=70\\\\y(t)=60t$

t is time

Net displacement is given by :

$z(t)=\sqrt{(60t)^2+(70)^2}$

Differentiating above equation wrt t as :

$z'(t)=\dfrac{1}{2}(3600t^2+4900)^{-1/2}{\cdot} 7200t$

Put t = 4 s

$z'(4)=\dfrac{1}{2}(3600(4)^2+4900)^{-1/2}{\cdot} 7200(4)\\\\z'(4)=57.6\ m$

So, the train is moving with a speed of 57.6 m/s.

3 0

4 years ago

What carries an electric current through a solution?

sashaice [31]

Free ions. Negative ions have one extra electron, positive ions are missing an electron. Negative ions give up their extra electron easily. I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions.

8 0

3 years ago

A very long line of charge with charge per unit length +8.00 μC/m is on the x-axis and its midpoint is at x = 0. A second very l

Ainat [17]

Answer:

a. E=6.5*10^{5}N/C

b. E=-4.7*10^{4}N/C

Explanation:

We can use the result of applying the Gauss theorem to a infinite line of charge

$E=\frac{\lambda}{2\pi \epsilon_0 r}$

with r the perpendicular distance to the line of charge. The total field will be the sum of the contribution to the field by each line of charge.

E=E1+E2

we have

+8.00 μC/m

-6.00 μC/m

y=1m

(a) y2=0.2m

$E=\frac{8*10^{-6}\frac{C}{m}}{2\pi (0.2m)(8.85*10^{-12})\frac{C^2}{Nm^2}}+\frac{-6*10^{-6}\frac{C}{m}}{2\pi (0.8m)(8.85*10^{-12})\frac{C^2}{Nm^2}}\\\\E=7.9*10^{5}N/C-1.3*10^{5}N/C=6.5*10^{5}N/C$

(b) y3=0.616m

$E=\frac{8*10^{-6}\frac{C}{m}}{2\pi (0.616m)(8.85*10^{-12})\frac{C^2}{Nm^2}}+\frac{-6*10^{-6}\frac{C}{m}}{2\pi (0.384m)(8.85*10^{-12})\frac{C^2}{Nm^2}}\\\\E=2.33*10^{5}N/C-2.8*10^{5}N/C=-4.7*10^{4}N/C$

In this case the field is directed toward the line of charge placed in y=1m

8 0

3 years ago

Read 2 more answers