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3 years ago

9 What dimensions do we need a rectangular

Mathematics

1 answer:

wlad13 [49]3 years ago

3 0

Answer:

W=30m L=90m

Step-by-step explanation:

A =2,700 m²

L=W+60

we know that area of a rectangle is A=L*W so we sustitute what we know

A=L*W

2,700 = (W+60)*W distribute

2,700 = W² +60W subtract 2,700 from both sides

W²+60W-2,700 =0

solve the quadratic equation with quadratic formula or on the calculator on the graph and will get W= -90 and W=30. Reject the -90 value because we can not have negative measurements. Our solution is W=30

L=A/W=2,700/30=90

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BigorU [14]

Hello,

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The sum of x and it’s opposite is always zero?

jeka94

Answer:

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

$a-a =0$

Or in the other case:

$-a -(-a) =-a +a=0$

So then we can conclude that the expression is a general rule and is true

Step-by-step explanation:

For this case we can verify if the following expression is true or false:

The sum of x and it’s opposite is always zero?

If we want to proof this we need to show that for any number is true.

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

$a-a =0$

Or in the other case:

$-a -(-a) =-a +a=0$

So then we can conclude that the expression is a general rule and is true

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3 years ago

At noon, ship A is 50 km west of ship B. Ship A is sailing south at 10 km/h and ship B is sailing north at 20 km/h. How fast is

Lena [83]

So hmmm check the picture below

so, we're looking for dr/dt then at 4:00pm or 4 hours later

now, keep in mind that, the distance "x", is not changing, is constant whilst "y" and "r" are moving, that simply means when taking the derivative, that goes to 0

$\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=0+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{y\frac{dy}{dt}}{r}\quad 
\begin{cases}
\cfrac{dy}{dt}=30\\
r=130\\
y=120
\end{cases}
\\\\\\
\cfrac{dr}{dt}=\cfrac{120\cdot 30}{130}$

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2 years ago

HELP ME ANYONE ANYONE PLEASEEEEE I BEG FOR LOVE OF JESUS

soldi70 [24.7K]

Answer:

b. -84

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{a}{-7} - 7 = 5$

Step 2: Solve for a

Addition Property of Equality: $\displaystyle \frac{a}{-7} - 7 + 7 = 5 + 7$
[Simplify] Add: $\displaystyle \frac{a}{-7}= 12$
Multiplication Property of Equality: $\displaystyle -7 \cdot \frac{a}{-7} = 12 \cdot -7$
[Simplify] Multiply: $\displaystyle a = -84$

Step 3: Check

Plug in a into the original equation to verify it's a solution.

Substitute in a: $\displaystyle \frac{-84}{-7} - 7 = 5$
[Frac] Divide: $\displaystyle 12 - 7 = 5$
Subtract: $\displaystyle 5 = 5$

Here we see that 5 does indeed equal 5.

∴ a = -84 is the solution to the equation.

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2 years ago