Answer:
The original volume of the first bar is half of the original volume of the second bar.
Explanation:
The coefficient of cubic expansivity of substances is given by;
γ = ΔV ÷ (Δθ)
Given: two metal bars with equal change in volume, equal change in temperature.
Let the volume of the first metal bar be represented by , and that of the second by .
Since they have equal change in volume,
Δ = Δ = ΔV
For the first metal bar,
2γ = ΔV ÷ (Δθ)
⇒ Δθ = ΔV ÷ (2γ)
For the second metal bar,
γ = ΔV ÷ (Δθ)
⇒ Δθ = ΔV ÷ (γ)
Since they have equal change in temperature,
Δθ of first bar = Δθ of the second bar
ΔV ÷ (2γ) = ΔV ÷ (γ)
So that;
(1 ÷ 2) = (1 ÷ )
2 =
=
Thus, original volume of the first bar is half of the original volume of the second bar.
Answer:
± (.021 ) ohm
Explanation:
In the addition of two physical quantities , the uncertainties are simply added .
So , net uncertainty in the value of R will be
± (.007 +.014)
=± (.021 ) ohm
Answer:
power emitted is 1.75 W
Explanation:
given data
length l = 5 cm = 5 × m
diameter d = 0.074 cm = 74 × m
total filament emissivity = 0.300
temperature = 3068 K
to find out
power emitted
solution
we find first area that is π×d×L
area = π×d×L
area = π×74 ××5 ×
area = 1162.3892 × m²
so here power emitted is express as
power emitted = E × σ × area × (temperature)^4
put here all value
power emitted = 0.300× 5.67 × 1162.3892 × × (3068)^4
power emitted = 1.75 W
Answer:
<h2>157.5 kg.m/s</h2>
Explanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 35 × 4.5
We have the final answer as
<h3>157.5 kg.m/s</h3>
Hope this helps you