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nignag [31]
2 years ago
14

A ball is dropped from the top of a building. The gravitational force is 10 N down, and the force of air resistance is 1 N up. W

hat is the net force?
9 N up
9 N down
11 N up
11 N down​
Physics
1 answer:
IgorLugansk [536]2 years ago
3 0

Answer:

Explanation:

The gravitational force acting on the ball, F = 10 N (down) The air resistance acting on the ball, f = 1 N (up) We need to find the magnitude of net force acting on the ball. The net force is given by : F' = 9 N. So, the net force acting on the ball is 9 N in downward direction. Hence, this is the required solution

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A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a
stira [4]

Answer:

Explanation:

Given

acceleration is given by

a=-g-c_Dv^2

where \ddot{y}=a

\dot{y}=v

Also acceleration is given by

a=v\frac{\mathrm{d} v}{\mathrm{d} s}

ds=\frac{v}{a}dv

\int ds=\int \frac{v}{-g-0.001v^2}dv

\Rightarrow Let -g-0.001v^2=t

-0.001\times 2vdv=dt

vdv=-\frac{dt}{0.002}

at\ v_0=50\ m/s,\ t=-g-0.001(50)^2

t=-g-2.5

at v=0,\ t=-g

\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}

\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}

s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}

s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})

s=113.608\ m

when air drag is neglected maximum height reached is

h=\frac{v_0^2}{2g}

h=\frac{50^2}{2\times 9.8}

h=127.55\ m

3 0
3 years ago
Samples of different materials, A and B, have the same mass, but the sample
Effectus [21]

Answer:

B. The particles that make up material B have more mass than the

particles that make up material A.

Explanation:

3 0
3 years ago
What is the correct answer?
damaskus [11]

Answer:

96 million of dollars

Explanation:

p=-6x^3+72x

p=-6(2)^3+72(2)

p=-6(8)+144

p=-48+144

p=96

8 0
2 years ago
Tooth fillings are often made of gold or porcelain because these materials are ______.
garri49 [273]
Tooth fillings are often made of gold or porcelain because these materials are nonreactive.

b. nonreactive.
4 0
3 years ago
Read 2 more answers
Four different resistors have various amounts of electric current flowing through them. Given the values of current I and resist
Artemon [7]

You did not provide the options. However, the options are

I = 6.0, R= 4.0 ohms

I = 9.0, R= 2.0ohms

I = 3.0, R= 2.0ohms

I = 8.0, R= 8.0 ohms

Answer:

The order of  the resistors from the highest to the lowest is:

I = 8.0, R= 8.0 ohms

I = 6.0, R= 4.0 ohms

I = 9.0, R= 2.0ohms

I = 3.0, R= 2.0 ohms

Explanation:

ohm's law states that voltage across a conductor is directly proportional to the current flowing through it.  V = IR

Based on this formula, the voltages in each of the resistors are calculated below from the highest to the lowest

  • For I = 8.0, R= 8.0 ohms

       V = 8 * 8 =64 volts

  •  For I = 6.0, R= 4.0 ohms

      V = 6 * 4 =24 volts

  • For I = 9.0, R= 2.0 ohms

       V = 9 * 2 =18 volts

  • For I = 3.0, R= 2.0 ohms

       V = 3 * 2 =6 volts

3 0
2 years ago
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