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BartSMP [9]
4 years ago
10

Question 3 (1 point)

Physics
1 answer:
g100num [7]4 years ago
3 0

Answer:

B) 18.5 m/

s west

Explanation:

Scalar quantity has MAGNITUDE only

Vector quantity has MAGNITUDE and DIRECTION

Hope this is correct and helpful

HAVE A GOOD DAY!

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A battery has a terminal voltage of 12.0 V when no current flows. Its internal resistance is 2.0 Ω. If a 4.6 Ω resistor is conne
rosijanka [135]

Answer:

Check attachment for solution

Explanation:

Given that 12V battery

5 0
3 years ago
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You have 1.2kg of (AU)gold (that's quite a bit of money at $1839/ounce). Using a heat source you apply 3096 J to the gold and re
melamori03 [73]

Answer:

129 J/Kg°C

Explanation:

Given :

Mass of gold, m = 1.2kg

Quantity of heat applied, Q = 3096 J

Temperature, t2 = 40°C

Temperature, t1 = 20°C

Change in temperature, dt = (40-20)°C = 20°C

Using the relation :

Q = mcdt

Where, C = specific heat capacity of gold

3096 = 1.2kg * C * 20°C

3096 J = 24kg°C * C

C = 3096 J / 24 kg°C

C = 129 J/Kg°C

7 0
3 years ago
Using Mirror equation A, Calculate The Frequency Of The Long Stand And The Shortest Wave Length Of That An Object Is Placed Of A
Leya [2.2K]

The Image distance and Magnification of The Image ​will be 30 cm and 3.

<h3>What is focal length?</h3>

The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.

Given data;

Focal length,f=?

Image distance,v=?

Object distance,u= 10 cm

Magnification,m= 2.85

The focal length is half of the radius;

f=R/2

f=30 Cm/2

f= 15 Cm

The mirror equation is found as;

\rm \frac{1}{f} =\frac{1}{v} +\frac{1}{u} \\\\\ \frac{1}{15}=\frac{1}{v}+\frac{1}{10} }  \\\\\ v= -30 \ cm

The magnification of the lens is found as;

\rm m=\frac{30}{10}\\\\ m=3

Hence, the image distance and magnification of The image ​will be 30 cm and 3.

To learn more about the focal length refer;

brainly.com/question/16188698

#SPJ1

6 0
2 years ago
Can i please get some help with this.
Ivenika [448]

the answer is D cuz electricity is a conductive

5 0
4 years ago
The gamma ray released by each decay carries 140kev of energy. find the total energy e released by decays in the 2 hours.
olya-2409 [2.1K]
First, we would need to know the decaying isotope.
Next, we use the decay formula
A = Ao e^(-kt)
After determining the remaining amount after two hours, the decay reaction can be used to determine the number of gamma rays released. If the given is in terms of mole, then the total energy is
E = 140n KeV where n is the number of moles of gamma rays released
8 0
3 years ago
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