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andreyandreev [35.5K]
2 years ago
6

Moons gravity and its comparison with earths gravity

Physics
2 answers:
noname [10]2 years ago
8 0
The acceleration of gravity on the moon's surface is 1.62 meters per second² .

That's 16.5% of its value on the Earth's surface.
kumpel [21]2 years ago
6 0
THE MOONS GRAVITY IS 1/6 OF THE EARTH'S GRAVITY THAT IS MOON'S GRAVITYIS VERY LESS THAN THAT OF EARTH.
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A single-turn square loop carries a current of 16 A . The loop is 15 cm on a side and has a mass of 3.8×10^−2kg . Initially the
DiKsa [7]

Answer:

The minimum magnetic field is 0.078 T.

Explanation:

Given that,

Current = 16 A

Side = 15 cm

Mass m= 3.8\times10^{-2}\ kg

Mass each segment in given square loop is

m=\dfrac{3.8\times10^{-2}}{4}

We need to calculate the torque due to gravity

Using formula of torque

\tau_{g}=2mg(\dfrac{L}{2})+mgL

\tau_{g}=2mgL

The torque due to magnetic field

\tau_{B}=FL

\tau_{B}=BIL^2

The equilibrium condition

\tau_{B}=\tau_{g}

Put the value into the formula

BIL^2=2mgL

B=\dfrac{2mgL}{IL^2}

B=\dfrac{2mg}{IL}

Put the value into the formula

B=\dfrac{2\times\dfrac{3.8\times10^{-2}}{4}\times9.8}{16\times15\times10^{-2}}

B=0.078\ T

Hence, The minimum magnetic field is 0.078 T.

7 0
3 years ago
A 0.0382-kg bullet is fired horizontally into a 3.78-kg wooden block attached to one end of a massless, horizontal spring (k = 8
wel

Answer:

280.87 ms⁻¹

Explanation:

Consider the motion of the bullet-block combination after collision

m = mass of the bullet = 0.0382 kg

M = mass of wooden block = 3.78 kg

V = velocity of the bullet-block combination after collision

k = spring constant of the spring = 833 N m⁻¹

A = Amplitude of oscillation = 0.190 m

Using conservation of energy

Kinetic energy of  bullet-block combination after collision = Spring potential energy gained due to compression of spring

(0.5)(m + M)V^{2} = (0.5)kA^{2}

(0.0382 + 3.78)V^{2} = (833)(0.190)^{2}

V = 2.81 ms⁻¹

v_{o} = initial velocity of the bullet before striking the block

Using conservation of momentum for the collision between bullet and block

m v_{o} = (m + M) V

(0.0382) v_{o} = (0.0382 + 3.78) (2.81)

v_{o} = 280.87 ms⁻¹

7 0
3 years ago
An 880n box is pushed across a level floor for a distance of 5.0m with a force of 440n. how much work was done on the box
Simora [160]
W=Fd, F=440N, d=5m. 5x440=2,200J of work
8 0
3 years ago
Read 2 more answers
The three osicles known as the hammer, anvil and stirrup __________.
34kurt
Malleus, incus, and stapes, respectively, and collectively, as "middle ear ossicles<span>".</span>
3 0
3 years ago
Start from 0 m/s and accelerate at 2m/s? Calculate the speed in m/s after acceleration for 5 seconds.
valentinak56 [21]

Answer:

10m/s

Explanation:

2m/s  x  5s=10m/s

4 0
2 years ago
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