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rusak2 [61]
4 years ago
7

A ray in plastic has a critical angle of 44.4 deg when trying to enter air. What is the index of refraction for the plastic?

Physics
1 answer:
Elena-2011 [213]4 years ago
8 0

Answer: 1.43

Explanation:

Given that:

C (critical angle) = 44.4°

n (refractive index of plastic) = ?

Apply the formula n = 1/sineC, the index of refraction for the plastic can be obtained by:

n = 1/sineC

n = 1/sine 44.4°

n = (1/0.6996)

n = 1.43

Thus, the index of refraction for the plastic is 1.43

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А masd<br>Of 500kg a raised to a height of 6m In 30s<br>Find (a) Workdone .​
Mazyrski [523]

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

5 0
3 years ago
From measurements on a uniformly sized material from a dryer, it was found that the surface area of the material is 1200 m2. If
amm1812

Answer:

D = 2.07\times 10^{-4} m

Explanation:

We know that the volume of the material

= mass/density

mass= 360 Kg

density = 1450 kg/m^3

Volume= 360/1450= 0.248 m^3

and Volume = Area× equivalent Diameter

Area= 1200 m^2

⇒Equivalent Diameter= Volume/Area= 0.248/1200=

D = 2.07\times 10^{-4} m

3 0
3 years ago
A dvd drive has a maximum speed of 72000 revolutions per minute. if a dvd has a diamter of 12 what is the linear speed
Brilliant_brown [7]
The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
P=2\pi.R
Know recall that:
v=\frac{d}{t}
We now need to know how much distance is traveled during a minute or 60 seconds:
D=7200\times 2\pi\times R
Finally we divide this result with t=60 seconds:
v=\frac{7200\times2\pi\times R}{60}&#10;\\&#10;R=\frac{12}{2}=6&#10;
v\approx 4523.89 \frac{units}{second}
Where the distance units were named units as the length unit is not specified in this exercise.<span />
7 0
4 years ago
Benjamina started her walk from the front door of her ground floor apartment. She walked 6 meters to the corner of the building
Cloud [144]
The distance is the total distance she walked which is 16 meters adding the 6 meters to the corner and 10 meters to her friend's apartment. Her displacement is the distance from her original starting point so you set up a triangle with side lengths of 6 and 10 and solve for the hypotenuse which gives you a displacement of 11.66 meters.  
5 0
4 years ago
Read 2 more answers
In a 4.0-kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third k
Svetlanka [38]

As per the question the total distance is given as 4 km.

We are asked to calculate the average speed.

The time taken by the body to travel each kilometre are 5.9 min,6.2 min.,6.3min. and 6 min. respectively.

The average speed of a body is defined as the ratio of total distance travelled by the body to the total time.

Mathematically the average speed is written as _

V= Total distance/Total time

i.e V = S/T

Where S is the total distance travelled and T is the total time

Here total distance (S)= 4 km

The total time T= (5.9+6.2 +6.3+ 6.0 )minutes

=24.4 min.

Hence average speed V = 4 km/24.4 min

= 0.16 km/min.

Hence the correct option is A .


3 0
3 years ago
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