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rusak2 [61]
3 years ago
7

A ray in plastic has a critical angle of 44.4 deg when trying to enter air. What is the index of refraction for the plastic?

Physics
1 answer:
Elena-2011 [213]3 years ago
8 0

Answer: 1.43

Explanation:

Given that:

C (critical angle) = 44.4°

n (refractive index of plastic) = ?

Apply the formula n = 1/sineC, the index of refraction for the plastic can be obtained by:

n = 1/sineC

n = 1/sine 44.4°

n = (1/0.6996)

n = 1.43

Thus, the index of refraction for the plastic is 1.43

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Frequency, period and wavelength<br> 11th grade high school physics
zzz [600]

Answer:0.38

Explanation:

the formula is f = c / λ

so f= 2.5/6.5

and that equals 0.38 46 and so on so i just rounded it

6 0
2 years ago
An element has the following natural abundances and isotopic masses: 90.92% abundance with 19.99 amu, 0.26% abundance with 20.99
sashaice [31]

<u>Answer:</u> The average atomic mass of the given element is 20.169 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of the isotopes each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i     .....(1)

We are given:

  • For isotope 1:

Mass of isotope 1 = 19.99 amu

Percentage abundance of isotope 1 = 90.92 %

Fractional abundance of isotope 1 = 0.9092

  • For isotope 2:

Mass of isotope 2 = 20.99 amu

Percentage abundance of isotope 2 = 0.26%

Fractional abundance of isotope 2 = 0.0026

  • For isotope 3:

Mass of isotope 3 = 21.99 amu

Percentage abundance of isotope 3 = 8.82%

Fractional abundance of isotope 3 = 0.0882  

Putting values in equation 1, we get:

\text{Average atomic mass}=[(19.99\times 0.9092)+(20.99\times 0.0026)+(21.99\times 0.0882)]

\text{Average atomic mass}=20.169amu

Hence, the average atomic mass of the given element is 20.169 amu.

4 0
3 years ago
12. An electric motor is plugged into a standard wall socket and is run- ning at normal speed. Suddenly, some dirt prevents the
rusak2 [61]

the answer would be B. the back emf increases, and the current drawn from the socket increases

more current is needed to make the motor move, like when you try to self crank a motor and the back wires are touching its harder to crank. and the emf increases since more current is being drawn in, strengthening the emf or increasing the emf

8 0
2 years ago
What does the dashed line represent in this diagram?
lys-0071 [83]
Motor branch circuit
8 0
2 years ago
A rod of length 20 cm has two beads attached to its ends. The rod with beads starts rotating from rest. If the beads are to have
exis [7]

Answer:

\alpha=28.57\frac{rad}{s^2}

Explanation:

We use the following rotational kinematic equation to calculate the angular acceleration of the rod:

\omega_f=\omega_0+\alpha t

Here \omega_f is the final angular speed, \omega_0\\ is the initial angular speed and \alpha is the angular acceleration. The rod starts rotating from rest (\omega_0=0):

\alpha=\frac{\omega_f}{t}(1)

Recall that the angular speed is defined in function of the tangential speed (v) and the radius (r) of the circular motion:

w_f=\frac{v_f}{r}(2)

In this case the radius is given by r=\frac{20*10^{-2}m}{2}=0.1m. Replacing (2) in (1):

\alpha=\frac{v_f}{rt}\\\alpha=\frac{20\frac{m}{s}}{(0.1m)7s}\\\alpha=28.57\frac{rad}{s^2}

5 0
3 years ago
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