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laila [671]
3 years ago
6

approximation to the average velocity in that time interval, what should be the sequence of calculations?Update the (vector) pos

ition of each objectSpecify the initial (vector) position of each objectSpecify an appropriate value for the time step Update the (vector) momentum of each objectCalculate the (vector) forces acting on the objectsSpecify the mass of each objectSpecify the initial (vector) momentum of each objectDefine constants such as G
Physics
1 answer:
Klio2033 [76]3 years ago
6 0

Answer:

The steps are outlined in the explanation below.

Explanation:

The average velocity is derived midpoint from the initial to the final velocity. Here is the proof:

Find the total displacement:

let the displacement be given by the letter s

Then since the average velocity is defined as:  v_{av}  = \frac{x - x_{0} }{t - t_{0} }

where t = final time

           t₀ = initial time

           v = final speed

           v₀ = initial time

where x denotes the position, then

v_{ave} = \frac{v+v_{0} }{2}

where v = \frac{dx}{dt} and dx = change in distance with respect to time.

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A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches
tiny-mole [99]

Answer:

26.8 seconds

Explanation:

To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:

v = final velocity

z = initial velocity

x = distance

t = time

a = acceleration

{v}^{2}  =  {z}^{2}  + 2ax

v = z + at

First let's find the final velocity the plane will have at the end of the runway using the first equation:

{v}^{2}  =  {0}^{2}  + 2(5)(1800)

v = 60 \sqrt{5}

Now we can plug this into the second equation to find t:

60 \sqrt{5}  = 0 + 5t

t = 12 \sqrt{5}

Then using 3 significant figures we round to 26.8 seconds

3 0
3 years ago
A force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg,
solmaris [256]
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6 0
3 years ago
A 180-ohm resistor has 0.10 A of current in it. what is the potential difference across the resistor
Firlakuza [10]
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V=18V
5 0
3 years ago
To solve a problem using the equation for keplerâs third law, enrico must convert the average distance of mars from the sun from
Natali5045456 [20]
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3 0
3 years ago
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An airplane undergoes the following displacements: First, it flies 40 km in a direction 30° east of north. Next, it flies 56 km
goldfiish [28.3K]

Answer:

Distance from start point is 72.5km

Explanation:

The attached Figure shows the plane trajectories from start point (0,0) to (x1,y1) (d1=40km), then going from (x1,y1) to (x2,y2) (d2=56km), then from (x2,y2) to (x3,y3) (d3=100). Taking into account the angles and triangles formed (shown in the Figure), it can be said:

x1=d1*cos(60), y1=d1*sin(60)\\\\ x2=x1 , y2=y1-d2\\\\ x3=x2-d3*cos(30) , y3=y2+d3*sin(30)

Using the Pitagoras theorem, the distance from (x3,y3) to the start point can be calculated as:

d=\sqrt{x3^{2} +y3^{2} }

Replacing the given values in the equations, the distance is calculated.

4 0
3 years ago
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