Answer:
54.3N
Explanation:
The normal force is perpendicular to the slope, so:
Normal Force = cos(37.2)(9.8*65).......507.39N
F(friction)=mu*F(normal)
F(friction)=(0.107)(507.39)
F(friction)=54.3N
Answer:
(a) surface area of the plate will be equal to 
(b) Charge on the capacitor is equal to 
Explanation:
We have given spacing between the plates d = 0.05 mm = 
Value of capacitance 
(A) Capacitance of a parallel plate capacitor is equal to 
So 

So surface area of the plate will be equal to 
(B) It is given that capacitor is charged by 1.5 volt
So voltage V = 1.5 volt
Charge on the capacitor is equal to 
So 
Answer:
The best choice would be c
Explanation: Sarah wants this wind turbine to efficient since she can only get one. C has the most reasonable option data collected will help her know the best wind speed over her farm.
the halogens is group 17,,
Answer:
mass consumed by 235U each day = 2 kg
Explanation:
electrical power produced = 1 GW = 1 × 10⁹ × (6.24151 × 10¹⁸ ) eV
= 6.24151× 10²¹ MeV/s
thermal energy = 0.420 * 250 = 105 MeV

= 5.94 × 10¹⁹ fission/second
=5.94 × 10¹⁹× 24 × 60 ×60)
= 5.13 × 10²⁴ fission/day
mu = 235.04393 × 1.660× 10 ⁻²⁷ = 390.1729× 10⁻²⁷ Kg
M = mu ×5.13 × 10²⁴
= 390.1729× 10⁻²⁷ ×5.13 × 10²⁴
M = 2 kg(approx.)
mass consumed by 235U each day = 2 kg