The circuit diagram below shows the locations of four switches. Which

A ball is thrown vertically downwards with a speed 7.3 m/s from the top of a 51 m tall building. With what speed will it hit the

ddd [48]

Answer:

32.46m/s

Explanation:

Hello,

To solve this exercise we must be clear that the ball moves with constant acceleration with the value of gravity = 9.81m / S ^ 2

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are the follow

$\frac {Vf^{2}-Vo^2}{2.a} =X$

Where

Vf = final speed

Vo = Initial speed =7.3m/S

A = g=acceleration =9.81m/s^2

X = displacement =51m}

solving for Vf

$Vf=\sqrt{Vo^2+2gX}\\Vf=\sqrt{7.3^2+2(9.81)(51)}=32.46m/s$

the speed with the ball hits the ground is 32.46m/s

8 0

2 years ago

Read 2 more answers

An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then

gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

$a=\frac{dv}{dt}=1.76$

So, the velocity can be obtained by integrating this expression:

$v=1.76t$

The velocity is, by definition: $v=\frac{dx}{dt}$ , so

$dx=1.76tdt\\x=1.76\frac{t^{2}}{2}$ .

Do x=11 in order to find the time spent.

$11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s$

At this time the velocity is: $v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}$

This velocity remains constant in the section 2, so for that section the movement equation is:

$x=v*t\\t=\frac{x}{v}$

The left distance is 89 meters, and the velocity is $6.2225\frac{m}{s}$ , so:

$t=\frac{89}{6.2225}=14.303s$

So, the total time is 14.303+3.5355s=17.838s

7 0

2 years ago

The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?

Anit [1.1K]

Answer:

The value is $Q_{net} = 1.239 *10^{-6} \ C$

Explanation:

From the question we are told that

The electric flux is $\Phi = 1.4*10^{5} \ N\cdot m^2/C$

Generally the net charge is mathematically represented as

$Q_{net} = \Phi * \epsilon_o$

Here $\epsilon_o$ is the permetivity of free space with value

$\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

So

$Q_{net} = 1.4*10^5 * 8.85*10^{-12}$

=> $Q_{net} = 1.239 *10^{-6} \ C$

8 0

2 years ago

Explain why the following statement is either true or false: The idea that all matter consists of the elements was first introdu

Dimas [21]

So i say false because 500 years is more than a few years but i could be wrong. Because of Aristotle’s idea that al matter is made up of only four elements it was accepted for over 2000 years but only around 500 years ago did scientists start discovering all of the elements known today.

4 0

2 years ago

A manufacturer sells two goods, one at a price of $1000 a unit and the other at a price of $16,500 a unit. A quantity q1 of the

vaieri [72.5K]

Answer:

manufacturing cost = $16.5 q₂ + $1 q₁ - $ 5

Explanation:

given,

one unit price of first good is = $ 1000

one unit price of second good is = $ 16500

quantity of the first good = q₁

quantity of the second good = q₂

total cost to the manufacturer = $ 5000

revenue from good one = $1000 q₁

revenue from second good = $16500 q₂

manufacturing cost = total revenue - total manufacturing cost

manufacturing cost = $16500 q₂ + $1000 q₁ - $ 5000

but in the question we have to answer in thousands of dollar

so, divide the result by 1000

manufacturing cost = $16.5 q₂ + $1 q₁ - $ 5

4 0

3 years ago