Answer:
The time required by object to achieve velocity 58 m/s is 5.918 second.
Given:
acceleration = 9.8 
Initial velocity = 0 m/s
final velocity = 58 m/s
To find:
Time required by object = ?
Formula used:
According to first equation of motion is given by,
v = u + at
Where, v = final velocity
u = initial velocity = 0 (Given The particle is at rest initially)
a = acceleration
t = time
Solution:
According to first equation of motion is given by,
v = u + at
Where, v = final velocity
u = initial velocity = 0 (Given The particle is at rest initially)
a = acceleration
t = time
58 = 0 + 9.8 (t)
t = 
t = 5.918 s
The time required by object to achieve velocity 58 m/s is 5.918 second.
Answer:
D species
Explanation:
According to the most widely used species definition, the biological species concept, a species is a group of organisms that can potentially interbreed, or mate, with one another to produce viable, fertile offspring. In this definition, members of the same species must have the potential to interbreed.
Answer:
Resultant displacement = 38.58 miles at an angle of 23.57° north of west.
Explanation:
Let north represent positive y direction and east represent positive x direction. Unit vector along x direction is represented by i and vector along unit vector along y direction is represented by j
Initial displacement = 17 miles north = 17 j miles
Final displacement = 24 miles at an angle of 40° west of north = 24 miles at an angle of 130° to positive x -axis
= (24 cos 130 i + 24 sin 130 j )
= (-15.43 i + 18.36 j ) miles
Total displacement = 17 j + (-15.43 i + 18.36 j) = -15.43 i + 35.36 j
Magnitude of displacement 
Angle to positive x -axis = tan⁻¹(35.36/-15.43) = 113.57°
Resultant displacement = 38.58 miles at an angle of 23.57° west of north.
Answer:
gravity
Explanation:
there eould be a different gravitational strenght on both of the planets causing it to weigh more, or less
Answer:
The magnitude of the applied torque is 
(e) is correct option.
Explanation:
Given that,
Mass of object = 3 kg
Radius of gyration = 0.2 m
Angular acceleration = 0.5 rad/s²
We need to calculate the applied torque
Using formula of torque
Here, I = mk²
Put the value into the formula
Hence, The magnitude of the applied torque is
