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givi [52]
3 years ago
9

A space station of diameter 20.0 meters is turning about its axis to simulate gravity at its center rim. How fast must it rotate

to produce an outer rim acceleration of 9.80 m/s^2 ?
Physics
1 answer:
bezimeni [28]3 years ago
4 0

Answer:

9.89 m/s

Explanation:

d = diameter of the space station = 20.0 m

r = radius of the space station

radius of the space station is given as

r = (0.5) d

r = (0.5) (20.0)

r = 10 m

a = acceleration produced at outer rim = 9.80 m/s²

v = speed at which it rotates

acceleration is given as

a = \frac{v^{2}}{r}

9.80 = \frac{v^{2}}{10}

v = 9.89 m/s

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) Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) . What are (a)
natali 33 [55]

To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.

The vector product between the Force and the radius allows us to obtain the torque, in this way,

\tau = \vec{F} \times \vec{r}

\tau = (8i+6j)\times(-3i+4j)

\tau = (8*4)(i\times j)+(6*-3)(j\times i)

\tau = 32k +18k

\tau = 50 k

Therefore the torque on the particle about the origen is 50k

PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,

cos\theta = \frac{r\cdot F}{|\vec{r}|*|\vec{F}|}

cos\theta = \frac{(8*-3)+(4*3)}{\sqrt{(-3)^2+4^2}*\sqrt{8^2+6^2}}

cos\theta = -0.24

\theta = cos^{-1} (-0.24)

\theta = 103.88\°

Therefore the angle between the ratio and the force is 103.88°

5 0
2 years ago
2. Jenny picks up a guitar and strums. If the sound from the string emanates out at 440 Hz,
erik [133]

Answer:

6.8×10^6 m

Explanation:

f = velocity of light/ wavelength

440= 3×10^8 / wavelength

so

wavelength = 3×10^7/ 44

= 6.8×10^6 m

7 0
3 years ago
A pitched ball is hit by a batter at a 45degrees angle and just clears the outfield fence, 98m away. Assume that the fence is at
Alex17521 [72]
The range of a projectile can be found directly using:
R = (v²sin2∅) / g
v = √((98 x 9.81)/(sin(90)))
v = 31.0 m/s
8 0
3 years ago
When a sound wave passes from air into water, what properties of the wave will change?
Alja [10]
<span>both the speed of the wave and the wavelength
- The frequency does not change, but the speed does. If that is true, then the wavelength must also change.</span>
3 0
2 years ago
A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. Which way(s) can increase the c
Charra [1.4K]

Explanation:

When an object moves in a circular path, due to the change in its velocity, the object possess centripetal acceleration. The formula for the centripetal acceleration is given by :

a=\dfrac{v^2}{R}

Where

v is the speed of the object

R is the radius of the circle path

Option (1) : Keeping the speed fixed and decreasing the radius by a factor of 9

a=\dfrac{v^2}{R/9}

a=\dfrac{9v^2}{R}

The centripetal acceleration of the ball by a factor of 9.

Option (2) : Keeping the radius fixed and increasing the speed by a factor of 3

a=\dfrac{(3v)^2}{R}

a=\dfrac{9v^2}{R}

The centripetal acceleration increases by a factor of 9.

Option (3) : Decreasing both the radius and the speed by a factor of 9.

a=\dfrac{(v/9)^2}{R/9}

a=\dfrac{(v)^2}{9R}

The centripetal acceleration decreases by a factor of 9.

Option (4) : Keeping the radius fixed and increasing the speed by a factor of 9

a=\dfrac{(3v)^2}{R}

a=\dfrac{9v^2}{R}

The centripetal acceleration increases by a factor of 9.

Option (5) : Increasing both the radius and the speed by a factor of 9

a=\dfrac{(9v)^2}{9R}

a=\dfrac{9v^2}{R}

The centripetal acceleration increases by a factor of 9.

Option (6) : Keeping the speed fixed and increasing the radius by a factor of 9

a=\dfrac{(v)^2}{9R}

a=\dfrac{9v^2}{R}

The centripetal acceleration increases by a factor of 9.

So, as the radius of the circle decreases, its centripetal acceleration increase. Also, if the speed of the object increases, its centripetal acceleration increase. Hence, this is the required solution.

4 0
3 years ago
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